Ammunition

Bullets fired from a rifled firearm should NOT tumble in flight. If they do so, it is a sign of problems.

This may be caused by different matters that all relate to the rifling in the firearm, and the bullet.

First is rifling is badly worn, if the bore is oversized for the bullet, or if rifling is badly fouled with lead/ jacketing metal/powder deposits, the bullet will not be gripped by the rifling and spun, and may not be stable in flight (tumbling) Try cleaning the bore properly, and check for excessive wear at the muzzle.

The second condition is the wrong weight/length of bullet for the rate of twist of the rifling. A fast rate of twist, combined with a very fast bullet, MAY result in the bullet "stripping", and not being spun by the rifling. Or a very heavy, slow bullet may not be spun fast enough to stabilize the bullet. Most .22 rimfire rifles are rifled to shoot 40 grain bullets accurately. If loaded with a 60 grain bullet, such as the Aguilla 60 gr SSS, the bullet will not be stabilized, and may tumble in flight.

To find the vertical height the pendulum rises, you can use the principle of conservation of energy. The initial kinetic energy of the bullet is converted into potential energy at the highest point of the swing. Use the equation: mgh = 0.5mv^2, where m is the mass of the pendulum, h is the vertical height, and v is the velocity of the bullet. Calculate the vertical height h to determine how high the pendulum rises.

There are spiral grooves engraved on the inside of a rilfe or pistol barrel. When a bullet is fired, it is forced into those grooves, which impart a spin to the bullet. The grooves are called rifling.

No- or minimal at best. Acceleration of the bullet comes from gas expanding inside the barrel, pushing the bullet. Once it leaves the barrel, (or within a VERY short distance) gas is no longer pushing, and acceleration stops, and bullet begins to slow from air resistance.

To reduce the velocity of a bullet in air, you can increase the drag force acting on the bullet by using a heavier or more aerodynamically shaped bullet, or by increasing the air density (e.g., shooting at higher altitudes). Additionally, you can decrease the initial muzzle velocity of the bullet by using a lower-powered cartridge or firearm.

Yaw refers to the rotation or deviation of a bullet's long axis from its original flight path. This can occur when a bullet destabilizes in flight, causing it to lose accuracy and potentially tumble upon impact. Yaw affects a bullet's stability and terminal ballistics.

Newton said "For every action, there is an equal and opposite reaction." The action is pushing the bullet in one direction. Reaction is the gun being pushed in the other. The energy is speed times mass. The gun masses much more than the bullet, and so will move proportionately slower than the bullet. Which is a very good thing- or the recoil of the gun would kill the shooter.

The speed at which a bullet drops due to gravity depends on multiple factors, including the caliber of the bullet, the initial velocity at which it was fired, and the angle at which it was shot. Generally, bullets drop at a rate of about 9.8 m/s² due to gravity. Wind resistance can also influence the rate of drop.

There is no single answer to this question. It will depend on the cartridge, and the characteristics of the powder and bullet being fired.

For instance, the 40 gr 22 Long Rifle cartridge accelerates from the moment of firing, until it travels about 12 inches. The gas produced by firing reaches it's max expansion, and the bullet now begins to SLOW to some degree from friction with the barrel.

Acceleration is NOT uniform with any firearm cartridge- if graphed it would be a curve with a very sharp spike.

Yes, a bullet fired straight up in the air can be lethal when it falls back down to the ground. The force of gravity causes the bullet to accelerate as it falls, potentially reaching a lethal velocity. This phenomenon is known as a "stray bullet" injury.

The fastest bullet speed belongs to the .220 Swift, reaching about 4,665 feet per second (1,422 meters per second).

No one answer to your question. This would depend on the particular alloy of titanium, how it is treated, and the bullet that it is trying to stop. Some very large caliber armor piercing bullets are VERY hard to stop.

1). Your speed in the forward direction should increase somewhat, since the recoil of the shot adds to your momentum. 2). The bullet you fire in the reverse direction leaves the muzzle with full muzzle velocity and momentum in the reverse direction ... in your frame of reference. Viewed by an observer in the stationary frame of reference ... the one in which you are moving at the speed of a bullet ... the one you fire just dribbles out of the muzzle and falls straight to the ground.

The force required to fire a 9mm bullet is generated by the gunpowder in the cartridge. When the firing pin strikes the primer, the gunpowder ignites, producing expanding gases that propel the bullet down the barrel. This force is typically measured in pounds or newtons.

No. The size-weight of the bullet also affects the knockdown power.

Power, kinetic energy, force and momentum: they are all related, and each one carries a 'mass' component.

It is, more expressly. the size of the Force or momentum of a moving object that determines its affect on other objects; and force and momentum are directly determined by both - the speed of the moving object and the size of its mass.

As it requires a greater force to move the larger bullet in the first place, which therefore means greater energy expended to do so, so at the other end that greater energy is conserved in the larger bullet, and therefore hits its target with greater force and energy.

When a bullet is fired from a gun, Newton's third law is applied as the bullet and the gun experience equal and opposite forces. The force pushing the bullet out of the gun is equal to the force pushing the gun backward, causing recoil. This relationship between the bullet and the gun follows the principle of momentum conservation.

When the triger is pulled, a pin in the barrel behind the cartridge is forced into the end of the cartridge igniting the powder charge. The ignition releases gasses under very high pressure which pushes the bullet out of the cartridge, down the barrel and to the target.

No, this statement is not true. When a rifle is fired horizontally, the bullet immediately begins to drop due to gravity as soon as it leaves the barrel. The rate of drop will depend on the muzzle velocity of the bullet and the distance it has traveled.

The fastest moving bullet can travel at speeds of around 4,000 feet per second (1,219 meters per second) for certain rifle bullets. These high velocities allow the bullet to cover a mile in less than two seconds.

The spinning motion of the bullet creates gyroscopic stability by resisting changes in orientation. This stability enables the bullet to maintain a straight path and resist tumbling or veering off course during flight. Additionally, the spin helps improve accuracy by minimizing the effects of external forces like air resistance.

a s.w.50 caliber or ( special weapons ) also known as the snipers weapon and is about 5.45" in length, either it has a red, black, silver or blue tip

That really didn't answer the question. Here is what you need to consider when trying to answer this question. #1 What is the weight of the bullet? If you're talking about a 750 grain .50 BMG, then it would not travel very far. Is this a Beowulf .50 cal or a Browning Machine Gun .50 cal? You can get exterior ballistics software on-line to calculate exactly what your looking for.

A bullet does not accelerate after it leaves the barrel of a gun. It will decelerate. You could say it accelerates, but the acceleration would be negative. The bullet is accelerated by expanding gas as it moves down the barrel, and after it leaves the muzzle, there is no more acceleration imparted from expanding gas. We also find that air friction (drag) is acting to slow it down. Think this one through and it becomes obvious.

Velocity of .50 BMG (Browining Machine Gun, 660 gr to 720 gr bullet weights ) projectile within 20 feet of the muzzle will between 2750 and 2850 feet per second, depending upon the cartride.
It depends on the weight and shape of the bullet, as well as the amount of powder used, but a good average would be from 2800 feet per second to a little over 3000 feet per second when shot from a rifle. There have been reports of greater speeds (in the 4000 to 5000 fps range) perhaps with sabot rounds.

The bullet will drop due to gravity as it travels, causing it to miss the target. Using the kinematic equation (s = ut + \frac{1}{2}at^2) where (s = 100 m), (u = 200 ms^{-1}), and (a = -9.81 ms^{-2}) (acceleration due to gravity), you can calculate the time it takes for the bullet to reach the target. Once you have the time, you can use the equation (d = \frac{1}{2}at^2) to determine how much the bullet will drop vertically and hence how much it will miss the target.

You do not mention which 9 mm cartridge you are asking about. As the 9mm Luger (parabellum) is the most popular handgun load in the world, I assume this is the one? The maximum listed range is about 2200 metres. Actual distance will vary depending on the grain weight of the bullet (for the 9mm luger, from 100 to 147), barell length, and other factors.