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Calculus
The branch of mathematics that deals with the study of continuously changing quantities, with the use of limits and the differentiation and integration of functions of one or more variables, is called Calculus. Calculus analyzes aspects of change in processes or systems that can be modeled by functions. The English physicist, Isaac Newton, and the German mathematician, G. W. Leibniz, working independently, developed calculus during the 17th century.
25,068 Questions
Whats property is used to solve the equation x plus 5 12?
Without an equality sign it is not an equation
What is the answer of the quadratic formula of 3x squared plus 7 equals 2x?
3X^2 + 7 = 2X
subtract 2X from each side and in standard form
3X^2 - 2X + 7 = 0
Use discriminant
b^2 - 4ac
(-2)^2 - 4(3)(7)
= 4 - 84 < 1
so, no real roots
How do you check your answer on 8x equals 5x plus 24?
The technique for checking your solution for an equation is always the same:
-- Take the original equation.
-- Wherever you see 'x', put your solution there instead of 'x'.
-- After you substitute your solution for all of the 'x's, look at the whole equation
and see whether the statement is true.
Example:
8x = 5x + 24
If my solution is x=1, then I have
8(1) = 5(1) + 24 ===> 8 = 5+24
The left side is 8, the right side is 29. They're not equal. The statement is false.
So my solution is wrong. 'x' is not 1.
If my solution is x=4, then I have
8(4) = 5(4) + 24 ===> 32 = 20 + 24
The left side is 32, the right side is 44. They're not equal. The statement is false.
So my solution is wrong. 'x' is not 4.
If my solution is x=8, then I have
8(8) = 5(8) + 24 ===> 64 = 40 + 24
The left side is 64. The right side is 64. They're equal. The statement is true.
So my solution is correct. 'x' is 8.
The step-work involved in proving this would be too long and detailed to show here, but the end result is this:
We're given three verticies, defined by the points (x1, y1), (x2, y2), and (x3, y3). We want to use them to define a parabola in this format:
f(x) = ax2 + bx + c
We can find our a, b and c coefficients with the following equations:
a = [y1(x2 - x3) + y2(x3 - x1) + y3(x1 - x2)] / [x12(x2 - x3) + x22(x3 - x1) + x32(x1 - x2)]
b = (y1 - y2) / (x1 - x2) - a(x1 + x2)
c = y1 - a(x12) - b(x1)
What are the plotting points for X equals 3?
for x=3 you plotting point will be a vertical line
for all input values of 'y' your output x will always be three therefore you will have a vertical line on the x-axis at 3 so you points would be ie (3,1) (3,2)(3,3) (3,4) so on and so forth.
What is the quadric equation for x2 2x 13 equals 0?
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
In any case, the quadratic equation IS x2 ± 2x ± 13 = 0 (depending on what the signs in the question are).
Is 18 x 52 stronger than 10 x 50?
Two numbers multiplied together produce a number. A number is neither strong nor weak.
Is 5 a solution to -3x plus 211?
( -3x + 211 ) is not an equation, so it doesn't have a 'solution'. It's not asking
a question, so it doesn't need an answer.
It's just an expression that stands for a number, and there's no way to tell
what number it stands for until you find out what number 'x' is .
If 'x' is 5, then the expression stands for the number 196 .
If 'x' is 17, then the expression stands for 160 .
If 'x' is 55, then the expression stands for 46 .
If 'x' is something else, then the expression stands for some other number.
How do you factor x2-20 plus 100 equals 0?
I'm guessing you meant to say x2 -20x +100. This equation is in ax2+bx+c=0 (1 is the "a" term, -20 is the "b" term, and 100 is the "c" term. You have to think to yourself, what factors of the "c" term (100) will add to the "b" term (-20) These factors are -10 and -10 because when you add these two terms you get -20 and when you multiply these two terms you get 100. Now your equations should read like this: (x-10)(x-10) = 0 . then you have to get x by itself by adding 10 to both sides. Thus, 10 is your factor.
Why can't we write equals in place of equals?
You can write "equals".
It would be perfectly fine to say "2 + 2 equals 4".
It's jsut that, it's much more common to use "=", just because it's easier probably.
1/3 - 2/(2y + 1) = 3/y
Provided that y ≠-1/2 and y ≠0,
multiply through by 3y(2y+1) to give
y(2y + 1) - 6y = 9(2y+1)
that is, 2y2 + y - 6y = 18y + 9
or 2y2 - 23y - 9 = 0
The quadratic formula then gives y = [23 ± sqrt{232 - 4*2*(-9)}]/(2*2)
= [23 ± sqrt(601)]/4
so that y = -0.3788 or y = 11.8788
