Calculus

1x-5x = -4x

But since you had the absolute value symbols surrounding it, change it to positive; so the answer is: 4x

You are asking for 3 points which solve:

-x + 2y = 2

We have both the x and the y on the same side of the equals sign, which doesn't help you very much. So our goal is to get y to be 'alone'. We call this "getting y in terms of x".

Since both the x and the y are of order 1, we know that this is a linear equation, so we expect that there are actually an infinite number of solutions.

-x + 2y = 2

2y = 2 + x

y = 1 + (1/2) *x

Now that we have the linear equation in slope-intercept form, we can simply plug in any 3 values that we want to get our answer. Try plugging in the numbers x=0, x=2 and x=4 as an easy example.

-5/7

I think x equals 2 or 4. I'm not really sure. It probably equals two, though.

Let's see... 4x+10=x+37

x = 9

-6

1780

2x3 + 2x2 = 2x2 * (x + 1)

infinity is 1+2+4+8+16...=?

so there is is nothing common because infinity does not equal anything( unless you get technical then it equals -1)

3

x = -2

It's not an equation and therefore unsolvable until it equals something.

x = 45

2x-7=5 + x

subtract x from both sides

(1)x-7=5

add 7 to both sides

x=12

∫ sin(x)/cos2(x) dx = sec(x) + C

C is the constant of integration.

x=4

8x2-10x-3 = (2x-3)(4x+1) when factored

62t = 82

divide both sides by 62

= 82/62

= 41/31

check ( use 82/62 )

62(82/62) = 82

as you see 62 cancels with 62

82 = 82

checks

7x+2 = 3x-2

7x-3x = -2-2

4x = -4

x = -1

Hmmm... That would be... 80 !

(x - 7) equals the number that is 7 less than whatever 'x' is,

and (x + 8) equals the number that is 8 more than whatever 'x' is.

You may have wanted us to do something with both quantities, (x-7) and

(x+8), but if so, we can't identify what it was. "And" is not a mathematical

procedure.

7

[ 62 - 63 = 1 ] is not an equation, and there's nothing to solve.

It's a simple, incorrect statement.

10