What is the integral of 2 1-x dx with limits 0 to t?
I think you meant the integral of 21-x dx, or as I write it ,/`21-x dx.
Use u-substitution where u = 1 - x. Note that the derivative of this equation is du = -1 dx, so we know dx = - du.
Rewriting the original integral in terms of u, integrating, then putting it back in terms of x gives us:
,/` 21-x dx
,/` 2u (-du)
- ,/` 2u du
- 2u / ln(2)
- 21-x / ln(2)
Note that the second to last line can be found in any integral table, and ln denotes natural log.
Now the bounds go from x = 0 to x = t, so:
[- 21-t / ln(2)] - [- 21-0 / ln(2)]
- 21-t / ln(2) + 2 / ln(2)
(-21-t + 2)/ln(2)
How do you solve 2x plus 6x minus 3 equals 13?
2X + 6X - 3 = 13
add 2X and 6X together
8X - 3 = 13
add 3 to each side
8X - 3 + 3 = 13 + 3
8X = 16
divide both sides integers by 8
(8/8)X = 16/8
X = 2
----------------check in original equation
2(2) + 6(2) - 3 = 13
4 + 12 - 3 = 13
13 = 13
checks
Why is a summation greater than an integral?
It's not. It depends on the method you use for summation whether
summation > integral
or
integral > summation.
3x=9 means 3 times a number is equal to 9.
Divide both sides by 3.
1) 3x/3=9/3
Dividing 3x by 3 cancels the 3 from the x.
2) 3x/3=9/3
Cleaning up the equation looks like this:
3) x=9/3
Solve the right side.
4) x=3
8 - x + 14 = 16x
We first attempt to isolate the variable and simplify the statement:
22 = 17x
Divide by 17, yielding only 'x'.
22/17 = 1 5/7
Suppose y varies directly with x and y equals 12 when x equals 6write an equation realting x and y?
y = kx ie y/x = k, k = 2, so y = 2x
What is the value of x if 7 divided by 2x equals 3?
7/2x = 3
Multiply both sides by 2x: 7 = 3*2x = 6x
Divide both sides by 6 = 7/6 = x ie x = 1.1666...
How do you write P x 9 x 3 x Q x P x 9 in exponential form?
92(P2Q) or 81(P2Q) is the best you can possibly do.
Which direction would the graph of yx plus 2 plus 3 open?
It is not possible to answer the question because there is no equation - only an expression.
What is x in the equation -9-6x plus 7x equals 1?
x=10
For the equation -9 - 6x +7x = 1
First, add nine to both sides to get all of the x's on one side
-9 - 6x + 7x = 1
+9 +9
-6x +7x = 10
Then, combine like terms on the left side
-6x+7x=10
x=10
How do you solve g x equals -3x plus 1?
If: x = -3x+1
Then: x+3x = 1 => 4x =1
So: x = 1/4 or 0.25
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I notice that the question requests a solution for g x = -3x + 1.
It seems possible that parentheses around the 'x' after the 'g' have gone missing, along with a prime indicating the derivative of the function g. This being the case, we would be seeking the antiderivative of -3x + 1.
The antiderivative of a sum is the sum of the antiderivatives. So we can look at -3x and +1 separately.
The derivative of x2 is 2x. Therefore, the antiderivative of x is x2/2, and the antiderivative of -3x is -3x2/2.
The antiderivative of 1 is x.
Overall, the solution is the antiderivative -3x2/2 + x + C, where C is an arbitrary constant.
What is 3x4 plus 5x3 plus x2 - 5 divided by x 2?
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =
(12 + 15 + x2 -5)/x2 =
(27 - 5 + x2)/x2 =
(22 + x2)/x2
What I mean by this equation is:
x^3-2x^(x-2.5)+x^(x^x)