NO!!!!

It can be converted to a rational fraction.

Method.

Let P 0.6666....

& 10P = 6.6666....

Subtract

9P = 6.0 = 6

P = 6/9

P = 2/3

With Irrational numbers you cannot convert to a fraction.

Casually an irrational number is one which goes to infinity, but the digits are not in any regular order. pi = 3.141592654.. is probably the most famous irrational number. Others being the square root (2) = 1.414213562....

and the square roots of prime numbers.

9.98 million = 9,980,000

In word it is said as 'Nine million, nine hundred and eighty thousand'.

1.35 is a rational number that can also be expressed as a fraction.

Irrational numbers can be roots because they are solutions to certain mathematical equations. For example, the square root of 2 is an irrational number that is a solution to the equation x^2 = 2. Similarly, other irrational numbers can be roots of different equations depending on their mathematical properties.

The square root of 25 simplifies to 5, and the square root of 75 does not have a simplified whole number value.

No, the square root of 432.8 is an irrational number because it cannot be expressed as a fraction of two integers.

Some examples of sets of real numbers include:

1. The set of positive integers: {1, 2, 3, 4, ...}
2. The set of rational numbers: {1/2, -3/4, 5/6, ...}
3. The set of whole numbers: {..., -2, -1, 0, 1, 2, ...}
4. The set of natural numbers: {0, 1, 2, 3, 4, ...}
5. The set of irrational numbers: {√2, π, e, ...}

The square of a rational number can be either rational or irrational. However, the square of an irrational number is always irrational.

NO!!!!

An irrational number is one were the decimal digits go to infinity and are not in any regular ordert.

Since 0.000125 terminates at the sixth decimal digit it does not go to infinity. Also irrational numbers cannot be converted to fractions. 0.000125 can be converted to a fraction.

Hence

0.000125 / 1.000000

Cancel down the decimal point, and the prefix zeroes.

Hence

125/1000000

Cancel down by '5'

25/200000

Cancel down again by '5'

5/ 40000

Cancel down by '5' again !!!!

1/8000

The answer!!!!!

NB

pi = 3.141592.... is the most well known irrational number.

Also the square roots of prime numbers e.g.

sqrt(2) = 1.414213562....

If you divide a rational number by an irrational number, or vice versa, you will ALMOST ALWAYS get an irrational result. The sole exception is if you divide zero (which is rational) by any irrational number.

Irrational numbers are non-repeating, non-terminating decimals. If your number repeats, it's rational. If it doesn't, it's irrational.

rational

NO !!!

However, the square root of '5' is irrational

5^(1/2) = 2.236067978...

Casually an IRRATIONAL NUMBER is one where the decimals go to infinity and there is no regular order in the decimal numbers.

pi = 3.141592.... It the most well known irrational number.

However, 3.3333.... Is NOT irrational because there is a regular order in the decimals.

Here is a definitive statement of irrational numbers. Irrational numbers are real numbers that cannot be represented as simple fractions. An irrational number cannot be expressed as a ratio, such as p/q, where p and q are integers, q≠0. It is a contradiction of rational numbers. Irrational numbers are usually expressed as R\Q, where the backward slash symbol denotes ‘set minus’. It can also be expressed as R – Q, which states the difference between a set of real numbers and a set of rational numbers.

Irrational

0.33333333333 is irrational, with the numeral 3 going on and on in that decimal.

rational

Assume = a/b with positive integers a und b. Now, for some natural number n define the functions f and F as follows. Strictly speaking, f and F should each have n as an index as they depend on n but this would render things unreadable; remember that n is always the same constant throughout this proof. Let f(x) = xn(a-bx)n/n! and let F(x) = f(x) + ... + (-1)jf(2j)(x) + ... + (-1)nf(2n)(x) where f(2j) denotes the 2j-th derivative of f. Then f and F have the following properties: f is a polynomial with coefficients that are integer, except for a factor of 1/n! f(x) = f(-x) 0

I'm assuming that you mean 'square root'. Yes, this sum is irrational. So are each of the two numbers alone. A simple proof can be done by writing x=square root 2 + square root 3 and then "squareing away" the square roots and then use the rational roots theorem. The sum or difference of two irrational number need not be irrational! Look at sqrt(2)- sqrt(2)=0 which is rational.

rational

is it

'Quarante' is the french word for forty.