Oxidation Numbers

In H2SO4, the oxidation number of H is +1, the oxidation number of S is +6, and the oxidation number of O is -2. These numbers are determined based on the rules of assigning oxidation numbers in compounds.

In the compound HF, the oxidation number of hydrogen (H) is +1 and the oxidation number of fluorine (F) is -1. This is because fluorine is more electronegative than hydrogen, so it takes on a -1 oxidation state while hydrogen takes on a +1 oxidation state.

The oxidation number of lead (Pb) in PbI2 is +2. Iodine (I) typically has an oxidation number of -1 in compounds. Since there are two iodine atoms in PbI2, the total negative charge contributed by iodine is -2. This balances with the +2 charge of lead to make PbI2 neutral.

The oxidation number of uranium can vary, depending on the compound it is in. In its most common form, uranium has an oxidation number of +6.

The oxidation number for hydrogen (H) is typically +1. Therefore, the total oxidation number for 6 hydrogen atoms would be +6.

The oxidation number for Al in AlF3 is +3. This is because fluoride (F) has an oxidation number of -1, and the overall compound is neutral, so the oxidation number of Al must be +3 to balance the charges.

Calcium is a element. Nitrate is a ion. Calcium shows +2.

The oxidation number of Cl in Cl2O7 is +7. In Cl2O7, there are 2 Cl atoms with an oxidation number of +14 total, and the oxidation number of O is -2 (since O usually has an oxidation number of -2 in compounds). Use the formula: 2x + 7(-2) = 0, which gives x = +7 for the oxidation number of Cl.

The oxidation states of halogens can range from -1 to +7. Fluorine typically has an oxidation state of -1, while the other halogens (chlorine, bromine, iodine) can have oxidation states from -1 to +7 depending on the compound and bonding.

In hemoglobin, iron predominantly exists in the +2 oxidation state, meaning it has lost two electrons. This allows it to bind oxygen molecules in red blood cells.

The oxidation number for manganese in manganese carbide (Mn3C) is +3. In the compound, there are three manganese atoms with a combined charge of +9, and one carbon atom with a charge of -3, resulting in a neutral compound.

The end product of oxidation depends on the substance undergoing oxidation. For example, the end product of oxidation of organic compounds can be carbon dioxide and water, while the oxidation of metals can result in metal oxides. In biological systems, the end product of oxidation of glucose is carbon dioxide and water, which releases energy in the form of ATP.

The oxidation number for Ra (Radium) is +2. Radium tends to lose two electrons to achieve a stable electron configuration.

You would get a linear curve because the oxidation state of elements in group 1 increases by one as you move from one element to the next, due to the loss of one electron in their outermost shell. Thus, the plot of oxidation state against atomic number for group 1 elements would result in a straight line.

The halogens (group 17) have an oxidation number of -1, though the halogens below fluorine can have other oxidation numbers as well. Hydrogen can also have an oxidation number of -1 when it forms hydrides.

The oxidation state (or number) is zero. This is true for any element in any of its allotropic elemental forms.

zero- H2 is the elemental form- by definition the ON# is zero

The molecular formula should be CBr4.

The oxidation numbers are -1 for each Br, +4 for C.

The known oxidation numbers of chromium are +2, +3, and +6, while the known oxidation numbers of selenium are -2, +4, and +6. Within this constraint, the only oxidation numbers that can match the formula given are -2 for selenium and +2 for chromium.

The oxidation state of Cl in HClO4 is +7. In HClO4, since the oxidation state of H is +1 and that of O is -2, the sum of the oxidation states in the compound must equal 0. Therefore, the oxidation state of Cl in this case is +7.

Oxidation numbers help determine the correct ratio of elements in a compound. By assigning oxidation numbers to each element, it is possible to balance the charges to show a neutral compound. The sum of the oxidation numbers in a compound should equal zero for a neutral compound or the overall charge for an ion.

An oxidation number is a measure of the charge that an atom would have if the bonding were ionic. It indicates the number of electrons that an atom would gain or lose in a chemical reaction. Valence electrons are the outermost electrons in an atom’s electron cloud and play a key role in determining the oxidation number of an atom.

Oxidation is needed when a substance needs to lose electrons to become more stable or to form a more favorable chemical bond. It is determined by the specific reaction occurring and the valence state of the elements involved. Oxidation can also be influenced by factors such as the presence of catalysts or the thermodynamic favorability of the reaction.

The oxidation number of an atom with 12 protons is +2. This is because the number of protons in an atom determines its atomic number, which also corresponds to its charge in simple cationic compounds.

Following the IUPAC definition method (typically taught in the US) O is with few exceptions -2 , H is +1 in this instance (it is only -1 when linked to a reactive metal). Therefore as the overall oxidation state of the molecule is zero as it is uncharged the oxidation number of C is 0.

Other answers are possible as there are other ways to work it out

a previous contributor offered this answer:-

To get the oxidation number for COH2 can be calculated by adding the oxidation of the individual elements. COH2 C is (+4), 2H is (-2) and O is (-2) which equals to 0.