Oxidation Numbers

The oxidation number of Cr in Cr2O7^2- is +6. This is because the overall charge of the dichromate ion is 2-, and each oxygen atom has an oxidation number of -2. By setting up and solving an equation representing the total charge of the ion, we can determine the oxidation number of Cr.

1+x+(-2)=0

1+x-2=0

x=2-1

x=1

thus oxidation number of chlorine is 1 in hclo

The oxidation number of chromium (Cr) in dichromate ion (Cr2O7^2-) is +6. This is because oxygen (O) is typically assigned an oxidation number of -2, and the overall charge of the ion is -2, so the two chromium atoms must have a total oxidation number of +12 to balance the charge.

The oxidation number of Br in BrO3 is +5. This is because the oxidation number of oxygen is usually -2, and since there are three oxygen atoms in BrO3, the total negative charge from oxygen is -6. To balance the charge of the compound which is neutral, the oxidation number of Br is therefore +5.

There are 3 elements. This is meta phosphoric acid.

It's an oxonium ion, but specifically it's the hydronium ion. Oxonium means any positively charged ion where an oxygen atom has three bonds (a double bond and a single bond count as three bonds).

+5. Oxygen is more electronegative than nitrogen and will exist in its most common -2 oxidation state. The three oxygen atoms in this ion therefore have a total charge of -6,requiring a formal charge on nitrogen of +5 to result in the charge -1 on the anion overall.

+1 to each H

+4 to each C

-2 to each O

The oxidation number of sodium in sodium chloride (NaCl) is +1, and the oxidation number of chloride is -1. Sodium tends to lose one electron to achieve a stable octet, giving it a +1 oxidation state, while chloride tends to gain one electron to achieve a stable octet, resulting in a -1 oxidation state.

The oxidation number of an ion is the charge of the ion, which is determined by the number of electrons gained or lost by the atom to achieve a stable electron configuration. Positive ions have oxidation numbers that equal their charge, while negative ions have oxidation numbers that are the negative of their charge.

In ionic compounds, the oxidation number is determined by the charge associated with each ion. For cations, the oxidation number is the same as the charge on the ion. For anions, the oxidation number is the negative of the charge on the ion. The sum of the oxidation numbers in an ionic compound must be zero.

The oxidation number for Mn in H2MnO3 is +3. In this compound, oxygen is typically assigned an oxidation number of -2, and hydrogen is +1. By considering the overall charge of the compound and assigning hydrogen and oxygen their usual oxidation states, the oxidation number of Mn can be calculated as +3.

The oxidation number in NO2 is +4 for nitrogen and -2 for oxygen. In this molecule, nitrogen is assigned an oxidation number of +4 because it is more electronegative than oxygen, which is typically assigned an oxidation number of -2 in compounds.

Fluorine's oxidation number is -1. Since there are four fluorine atoms, the total oxidation number for the fluorine portion of the molecule is -4. The carbon atomwould have to have an oxidation number of +4 so that the compound would have an overall oxidation number of 0.

The oxidation number for copper metal is 0. This is because copper atoms in their elemental form have a neutral charge, with an equal number of protons and electrons.

The oxidation number of silver (Ag) in AgCl is +1. This is because chlorine (Cl) has an oxidation number of -1 in most compounds, so the overall sum of the oxidation numbers must be zero for a neutral compound like AgCl.

The oxidation number for H in H3PO2 is +1, as it is in compounds with nonmetals. The oxidation number for P in H3PO2 is +1, as the sum of oxidation numbers in a compound is zero.

zero bcoz the oxidation no of element in free state is zero

Oxygen atoms are generally considered to have an oxidation number of -2 in all oxyanions such as sulfate.

In CaC2, the oxidation number of the Ca atom is +2 because it is a group 2 element. The oxidation number of the C atom is -2 because it typically forms covalent bonds with other elements, resulting in a formal charge of -2 on each C atom in CaC2.

In MoCsAiD, titanium is likely in the +4 oxidation state. This is because in chemical formulas, the sum of the oxidation numbers of all atoms in a compound must equal the overall charge of the compound, and in this case, titanium is commonly found in compounds with a +4 oxidation state.

Chlorine typically has an oxidation number of -1 in its compounds, but to determine the oxidation number of Cl in Cl3, you would divide the total charge (+3) by the three atoms, resulting in an oxidation state of +1 for each Cl atom.

The oxidation number of Fe in Fe2O3 is +3 because oxygen typically has an oxidation number of -2 and there are 3 oxygen atoms for every 2 iron atoms in the compound, making the overall charge -6 for oxygen. To balance the charges, each iron atom must have a charge of +3.

Oxidation number of P in H3PO3 is +3. To calculate the oxidation number

H= 1 except when bonded to metal

O is -2 except when bonded to F

The sum of all of the oxidation number on a molecule /ion is equal to the charge so as H3PO3 is a neutral molecule:-

0 = OxP + 3OxH + 3OxO = Oxp + 3 + (-6)

Oxp = +3

H3PO3 is phosphorus acid. However when you try to make it in aqueous solution, it "tautomerises" , turning into phosphonic acid, HPO(OH)2- same formula H3PO3, but its got a P-H bond and a P=O bond. The oxidation number of P is still 3

The oxidation number of each copper (Cu) atom in CuCO3 is +2. The oxidation number of the oxygen (O) atoms in the carbonate ion (CO3) is -2, and the overall charge of the carbonate ion is -2.