Oxidation Numbers

The oxidation number for sulfur (S) in SO2 is +4. This is because oxygen (O) usually has an oxidation number of -2, and there are two oxygen atoms in SO2 with a total charge of -4. Therefore, to balance the overall charge of the compound (which is 0), sulfur must have an oxidation number of +4.

The oxidation number for Cl in Cl4 is -1. Since Cl is a halogen, it typically has an oxidation number of -1 when it forms compounds.

The oxidation number of Mn in manganese VII oxide is +7. This is because oxygen typically has an oxidation number of -2, and there are two oxygen atoms in manganese VII oxide, giving a total oxidation number of -4. To balance the compound's charge of 0, manganese must have an oxidation number of +7.

The octet rule states that atoms tend to gain, lose, or share electrons to achieve a full outer shell of eight electrons. By following this rule, you can determine the oxidation number of an element based on how many electrons it gains or loses in order to reach a full octet. The oxidation number corresponds to the charge an atom would have if the compound were ionic.

The oxidation number of iron in this compound is 3. The oxidation numbers of the total oxygen atoms and the total iron atoms must be the same in a neutral compound. There are three oxygen atoms, giving a total for oxygen of 3 X 2 = 6. There are only two iron atoms; therefore, each one must have an oxidation number of 6/2 = 3.

THe oxidation number for 'O3' is zero(0).

O3 is ozone, and each oxygen atoms forms two single bonds with each of the other oxygens, forming a triangular arrangement.

The oxidation numbers for the first 20 elements in the periodic table are typically as follows: Group 1 elements: +1; Group 2 elements: +2; Group 13 elements: +3; Group 14 elements: +4 or -4; Group 15 elements: -3; Group 16 elements: -2; Group 17 elements: -1; Group 18 elements: 0. Keep in mind that oxidation numbers can vary in different compounds and contexts.

The oxidation number of sulfur in SO32 is +4. This is because oxygen always has an oxidation number of -2, so the sum of the oxidation numbers in the compound must equal the charge of the ion, which is -2 for SO32.

The oxidation number of Cl in potassium chlorate (KClO3) is +5. This is because the oxidation number of K is +1 and the oxidation number of O is -2. By using the sum of the oxidation numbers in the compound, the oxidation number of Cl can be calculated to be +5.

The oxidation number of carbon (C) in acetic acid (CH3COOH) is +3. This is calculated based on the known oxidation numbers of hydrogen (+1) and oxygen (-2) combined with the overall charge of the molecule being neutral.

The oxidation number of phosphorus in PH3 is -3.

The sum of oxidation numbers in a neutral compound is always zero. (Note that in order for this to be true, the oxidation number of each type of atom present must by multiplied by the number of such atoms present in the formula unit for the compound before the addition is performed.)

The oxidation number of Fe in FeO (iron oxide) is +2. This is because oxygen typically has an oxidation number of -2, and in a neutral compound like FeO, the oxidation numbers must balance out to zero.

The elements in column 13 of the periodic table (Group 13) typically have an oxidation number of +3 in their compounds. This includes elements such as boron, aluminum, gallium, indium, and thallium.

The oxidation number for nitrogen in dinitrogen trioxide (N2O3) is +3. Each oxygen atom has a -2 oxidation number, totaling -6 for the three oxygen atoms. Since the overall charge of dinitrogen trioxide is zero, the two nitrogen atoms must have a total charge of +6, leading to an average oxidation number of +3 for each nitrogen atom.

Valence is how many bonds an atom can form. Oxidation number can be though of as being similar to the charge on an ion, and is based on the difference in electronegativity between bonded atoms. If something is bonded to a more electronegative element, its oxidation state is positive, and if it is with a less electronegative on the state is positive. In a neutral substance the sum of the oxidation states is always zero. Valence and oxidation states are related, though.

Example: In formaldehyde (CH2O) hydrogen has a valence of 1, oxygen a valence of 2, and carbon a valence of 4. Carbon is more electronegative than hydrogen, and less electronegative than oxygen. As a result, each hydrogen atom has an oxidation state of 1+ and the oxygen is in the 2- oxidation state. This puts carbon in an oxidation state of 0.

The oxidation number of N in N2 is 0 since it is in its elemental form. In a diatomic molecule like N2, each nitrogen atom has an oxidation number of 0.

Oxidation states of elements in Iodate anion:

Iodine = +5

Oxygen = -2

0 in elemental form

+3 in its compounds

Oxidation numbers generally become more positive from left to right across a period and more negative down a group on the periodic table. This trend is due to changes in the number of valence electrons as you move across and down the table, impacting how likely an atom is to gain or lose electrons.

The oxidation number for oxygen (O) in K2O2 is -1. In this compound, each oxygen atom has an oxidation number of -1, which is typical for peroxides like K2O2.

The oxidation number for gold (Au) in gold(III) arsenide (AuAs3) is +3. This is because arsenic (As) typically has an oxidation number of -3, and since the compound is neutral, the total oxidation numbers must balance out to zero.

The oxidation number for lead in lead(IV) dichromate is +4, while the oxidation number for chromium in dichromate is +6.

It must be equal to the charge on the compound/ion

The oxidation number of Ge in GeS2 is +4, as it belongs to group 14 on the periodic table and typically forms compounds where it has a +4 oxidation state. The sulfur atoms in GeS2 would have an oxidation number of -2 to balance the charge of the compound.