Probability

It is possible to choose 4 radios out of 23 in (23 choose 4)=8855 ways. The number of those combinations where there are exactly 2 indefective and 2 defective is: (18 (the number of those indefective) choose 2)*(5 (the number of defective radios) choose 2)=1530 divided by 8855=1530/8855=306/1771 which is 17.2784%.

The probability that there are 1,2,3 or 4 men is 1-(the probability that no men are selected). First we select the first person. The probability that this person is a woman is 5/10=1/2. For second person it is 4/9, then 3/8 and finally 2/7. We multiply these together: (1*4*3*2)/(2*9*8*7)=24/1008. This is the probability that every single person in the committee is a woman. One minus that probability is 984/1008=41/42 which is 97.619%

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you have about a 42% chance for that to happen

Probability is the chance (in percentage or decimal) of a particular event to happen.

lets say that you tossed a coin. the possible events to happen are ending up with heads or tails. the probability of having a head is 50% or .5 while the probability of having a tails is 50% or .5.

to solve for the probability, divide the particular event with the total number of possible events.

ex. what is the probability of getting a 3 when you rolled a dice?

particular event= having a 3= 1 event

total number of events= having either a 1, 2, 3, 4, 5, or 6= 6 events

particular event/ total number of events= 1/6

hoped i helped!

CALCULUS

i believe it would be a (1/4)^5 chance. if youre going that route, good luck

Random Variable in probability theory is defined as follows: Assuming you have variables Xi where i is an integer ie: i=1,2,3.......n a variable Xi is called a random variable iff(if and only iff) and random selection yields a variable Xi for i=1,2.........,n with the same likelihood of appearance. i.e prob(X=Xi)=1/n

Let us assume that there are exactly 365 days in a year and that birthdays are uniformly randomly distributed across those days.

First, what is the probability that 2 randomly selected people have different birthdays? The second person's birthday can be any day except the first person's, so the probability is 364/365.

What is the probability that 3 people will all have different birthdays? We already know that there is a 364/365 chance that the first two will have different birthdays. The third person must have a birthday that is different from the first two: the probability of this happening is 363/365. We need to multiply the probabilities since the events are independent; the answer for 3 people is thus 364/365 × 363/365.

You should now be able to solve it for 4 people.

p = 1 / Time » 2 X 10-7

You have a 1 in 2 chance of having a girl. No matter how many boys you have had in the past or how many girls you have had in the past, each pregnancy presents the opportunity to have a girl or a boy with a 50% chance. The sperm does not know that it had already produced ,say, 5 boys and needs to produce a girl for you and your partner. So with every pregnancy there is a 50% chance you will have a girl and a 50% chance you will have a boy.

If you look at the link below, the probability of a 28 year old female having a baby with Down syndrome is a little less than 1 in 1000.

Since the probability of getting tails is 50% or 0.5, the probability of three tails would be 0.5*0.5*0.5=0.125 or 12.5 %

The probability will b 0.5. since a coin tossed n times has 2n no. of desired results, among which only half that is n times it can b tail. Hence P = n/2n i.e 0.5.

Using prime factorization, there are 2 three digit numbers with 9 factors:

512 and 768.

There are no three digit numbers with 10 or more prime factors.

512=2^9 and 768=3*2^8

If the probability of a person being left handed is .11, then the probability of a person being right handed is .89 (1.00 - .11). In a class of 40 people, there are 40! (40 factorial) = 40 x 39 x 38 x .... x 3 x 2 x 1 possible Permutations of students. Within this number, there are many that will yield exactly 5 left handed people. 40-P-5 is the number of Permutations of 5 within a class of 40 (sorry, can't use the correct formating here!): = 40! / (40 - 5) ! = 40! / 35! = 40 x 39 x 38 x 37 x 36 Since we don't care about order..... we need to factor out the number of identical permutations. 40-C-5 = 40-P-5 / 5! So.... (40 x 39 x 38 x 37 x 36) / (5 x 4 x 3 x 2 x 1) = 658,008 Now, what is the probability of any one such combination? (.89 to the power 35) x (.11 to the power 5) = 0.000000273 So the probability of exactly 5 left handed people in the class is 658,008 x .000000273 = 17.9408137 %

0.205

0.894

This is the same as example 2 in the link below

Edge

If you have primary school age children then the likelihood of them getting head lice (repeatedly!( these days is very high - believe me! Chances are you will have them too at some point. Other than that, I would think your chances of catching them are quite low.

To stop yourself being scared the best thing to do is to realise that it happens to lots of normal people, and to lots of normal people's children. You get a more realistic picture when you realise that - it is not a major catastrophe, nor something that can't be fixed. They can even be eradicated naturally - it just takes patient combing with a fine tooth comb - for a few weeks to ensure none are left.

One way to keep them away, there is home remedy.. it conset of rosemary poppuri a lil of olive oil, (because you don't want to dry out the sclap with the poppuri) so u mix it all up! apply around the edges of the hair. where lice tend to enter.. for sum reason the lice don't like it... so there u have it good luck.. if this works for u let me no!! muah...

Why be scared lol it happens you just need to get the right stuff to put on your hair.... and...... bobs your uncle!!!!! well he's my dad but you get my point

9 times 9 times 9 times 9 times 9 times 9 times 9 times 9 times 9 =

Imagine it's a combination lock with 9 tumblers. Each tumbler has 9 "positions" - the digits from 1 to 9. So you multiply the number of digits [9] against itself [9] for as many tumblers are in the combination (9).

Tumbler # 1 2 3 4 5 6 7 8 9

Number of

possible

digits 9 9 9 9 9 9 9 9 9

lol answer it for urself dont rely on this ,this is troll