Probability

people eat chees often

well if you take the four out of the seven its 4/7 convert that into a percent wich equals 57%

5/8 lol....

You should ask the dealer what the proper indication is. Usually the desire to be hit in Blackjack is indicated by bending a finger towards you, in a "come here" sign, or by pointing down at the cards, but this could be confused with the stay command which is usually a flat open hand over the cards. Go with my first recommendation and ask the dealer.

It is a progression of terms whose reciprocals form an arithmetic progression.

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The answer will depend on the product. If the economy is strong the sales of inferior goods will fall. Also, it depends on the level at which the sales are currently.

Three out of twelve

8 were defective while (75-8=67) weren't. So the estimated probability that a flyer won't be defective is 67/75

There are eight possible outcomes: HHH, HHT, HTT, HTH, TTT, TTH, THH, THT. Of these, 3 contain two tails: HTT, TTH, and THT and the probability of getting two tails is 3/8. If the question were 'getting at least two tails' then TTT would need to be included for a probability of 4/8 or 0.5.

The probability is 3/8 = 0.375

Let's break this down and see what we can do with it. First, the probability of transition of an atom from the initial state (m) to final state (n) will depend on what it is that is transitioning, and also on how it's transitioning. Which element - and which isotope - is transitioning? And how it is transitioning? Under what conditions? Radioactive decay? Neutron (or other particle) absorption? With the stating atom and the mode of change, we can determine the probability of transition as was asked. With the first part of the information in hand, we can determine the energy loss in the heavy charged particle emission event. We should also be able to determine the time over which the event takes place, and then discover the rate of energy loss (though it will represent only an average) for said event.

The range of a number set is the difference between the highest number and the lowest number in the set. To find the range, you subtract the smallest number from the largest number.

The odds are 220:1 of being dealt pocket aces.

1 - P (1 or 0) =

1 - P(1) - P(0) =

1 - ((4 above 1) * 0.5 * 0.5^3) - ((4 above 0) *0.5^4) =

1 - (4/16) - (1/16) =

1- (5/16) =

11/16

zero...

When two fair coins are tossed, you have the following possible outcomes:

HH, HT, TH, TT.

So, at most implies that you get either i) zero heads or ii) one head.

From the possible outcomes we see that 3 times we satisify the outcome.

Thus, probability of at most one head is 3/4.

The probability is 0.5 regardless how many times you toss the coin."

To get the answer is simple. You just convert 67% to a decimal. It is 0.67. Then multiply by 5

0.67x 0.67 x 0.67 x 0.67 x 0.67 = 0.135

it is a ten sided and ten angled figure

The term "theoretical probability" is used in contrast to the term "experimental probability" to describe what the result of some trial or event should be based on math, versus what it actually is, based on running a simulation or actually performing the task. For example, the theoretical probability that a single standard coin flip results in heads is 1/2. The experimental probability in a single flip would be 1 if it returned heads, or 0 if it returned tails, since the experimental probability only counts what actually happened.

No because it isn't one of the normal counting numbers.

Each of the dice has 6 sides.

There are 6 x 6 = 36 possible combinations.

Of those, the following equal 5:

1 and 4

2 and 3

3 and 2

4 and 1

So the odds of rolling a 5 is

4 chances out of 36

4 / 36 = 1 / 9 That converts to a probability of 0.1111111...

4 7's

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