Probability

force over area=pressure

It is 0.3125

The confidence interval becomes wider.

The probability of getting the queen of hearts is 1 in 52, or about 0.01923.

The probability of getting any queen is 4 in 52, or about 0.07692.

The probability of getting any heart is 13 in 52, or exactly 0.25.

A half.

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The sample space when flipping a coin is [heads, tails].

A negative deviation means that the observation is smaller than whatever it is that the deviation is being measured from.

The number of arrangements of the letters PARTY, if the first letter must be an A is the same as the number of arrangements of the letters PRTY, and that is 4 factorial, or 24.

The probability of rolling a six with a standard die five times in a row is (1 in 6)5 which equals 1 in 7776 or about 0.0001286.

Yes, it does. If the data are sample data, than the divisor is N. If the data are the entire population, than the divisor is N-1 is account for the loss of one degree of freedom in the calculation of both the mean and the standard deviation from the same data.

It is a measure of the spread of the distribution: whether all the observations are clustered around a central measure or if they are spread out.

A confidence interval of x% is an interval such that there is an x% probability that the true population mean lies within the interval.

There are 12 factorial or 479,001,600 permutations of the letters in the word SOCIOLOGICAL. However, since the letter O occurs three times, the letter I occurs twice, the letter L occurs twice, and the letter C occurs twice, you have to divide that by 8 (O), 2 (I), 2 (L), and 2 (C) giving you 7,484,400 distinctpermutations.

When a die is rolled once, the probability of 1 showing up is 1/6 .

When a die is rolled 14 times, the probability of 1 showing up 6 times is a binomial probability.

Let x = number of times 1 shows up

P(x=6) = 14C6 (1/6)^6 (5/6)^(14-6)

= 14C6 (1/6)^6 (5/6)^8 = 0.014982

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The probability distribution is

P(X = 1) = 1/36

P(X = 2) = 3/36

P(X = 3) = 5/36

P(X = 4) = 7/36

P(X = 5) = 9/36

P(X = 6) = 11/36

P = 0 otherwise.

Mean(X) = 4.4722

Variance = 1.9715

Range can include outliers that are not normal values and can skew overall data. Most relevant values can be found within one or two standard deviations on a normal curve.

There are 36 permutations of two dice. Of them, 6 have a sum of 7, (1+6, 2+5, 3+4, 4+3, 5+2, and 6+1) and 2 have a sum of 11 (5+6 and 6+5). The probability, then of getting a sum of 7 or 11 is (6 plus 2) in 36, or 8 in 36, or 2 in 9, or about 0.2222.

There are 26 = 64 possible outcomes.

6 possible numbers to land on the first time, 6 possible numbers to land on the second time, 6x6=36

also uncertain.

0.53 = 0.125.