Probability

There are 36 equally-likely possibilities for a 2-dice roll (six possibilities for each die, multiplied together). Let's consider the probability of the sum being less than or equal to 4. There is only one way to roll a 2 (1+1), there are two ways to roll a 3 (1+2, 2+1), and three ways to roll a 4 (1+3, 2+2, 3+1). So there are 6 ways to roll at most a 4, meaning that there must be 36-6=30 ways to roll more than a 4. The probabiliity of rolling a sum greater than 4 is therefore 30/36, or 5/6.

well the first 12 is in box number 10 the second is in box number 9 and it has 9 spades the third is in box number 2 and it has 4 spades and that's all 25 of them

A Z-Score of 0 separates the upper 50% of the area from the lower 50% of the area. A Z-Score of 0 is at the mean, median, and mode of the distribution.

There are 13 spades in a deck of cards, so the probability of drawing a spade is 13/52 or 1/4.

The probability of rolling one 6 is ( 1/6 ).

The probability of rolling seven 6's is ( 1/6 )7 = 3.572 x 10-6 = 0.0003572 percent

The probability of getting all heads is 1/24 = 1/16

The probability of getting all tails is also 1/24 = 1/16

The probability of all heads or all tails is the sum of the two = 1/8

1.0

The coin is traveling at the same velocity as the tosser, so it will land the same as if you were standing still.

8

4/13

7:1

The chance is one in 216 (6^-3).

The probability of rolling a five once is 1/6. Rolling a five again, on the same die or another, will still have a 1/6 chance. Therefore, the probability of the event occurring twice is 1/36 (1/6^2). Three times has a probability of 1/216 (1/6^3), and so on. It does not matter what die is used, as long as it has six sides.


The probability p of rolling a number x times consecutively on an s sided die is
p=s^-x

1 out of 12

The definition of mutually exclusive events is that the events can't occur at the same time. For example, you can't flip a coin and get a head and a tail; they are mutually exclusive events.

The probability of rolling doubles with two dice is 1 in 6, or about 0.167.

ratio

If two fair dice were rolled, there would be 36 outcomes.

(1,1),(1,2),....,(6,6)

The maximum sum would be 12.

Therefore, the probability that the total number of spots shown is equal to 15 is zero.

1/52

The probability of getting an odd number when you roll one die is 1 in 2. In order to get an odd sum with two dice, one of them has to be odd and one of them has to be even. The probability of rolling an odd sum is still 1 in 2, since each die is unrelated in probability to the other.

There are 36 outcomes for rolling 2 dice, and there is 1 way that a 12 can occur which is 6,6. So, the probability of rolling the sum of 12 on 2 dice is 1/36.

Since you need a specific number - the number 6 - twice, the probability is (1/6)2, which is equal to 1/36.

Since you need a specific number - the number 6 - twice, the probability is (1/6)2, which is equal to 1/36.

Since you need a specific number - the number 6 - twice, the probability is (1/6)2, which is equal to 1/36.

Since you need a specific number - the number 6 - twice, the probability is (1/6)2, which is equal to 1/36.

Mutually exclusive.

T-scores and z-scores measure the deviation from normal. The normal for T-score is 50 with standard deviation of 10. if the score on t-score is more than 50, it means that the person scored above normal (average), and vise versa. The normal for Z-score is 0. If Z-score is above 0, then it means that person scored above normal (average), and vise versa.

False

With a standard 6 faced die, numbered 1 through 6, there are three odd numbers, 1, 3, and 5, of which 3 and 5 are prime, and there is one even prime, 2. The probability, then, of rolling an odd number which is prime is 1 in 3, i.e. 3 or 5 out of a possible result set of 1, 2, 3, 4, 5, and 6.