Probability

You can roll (3,6), (4,5), (5,4), or (6,3). So that's four possibilities out of 36. So 4/36 or 1/9.

Every time you flip a coin it has a 50% chance of heads and a 50% chance of tails. Flipping a coin multiple times does not change that. Therefore the answer is 50%

Five numbers can be arranged in 5! = 120 ways.

The first roll doesn't matter for probability, it just sets the number to be rolled by the other two. So:

P(rolling the same number three times) = P(rolling a particular number)2 = (1/6)2 = 1/36

Low back pain

random sample is a big sample and convenience sample is small sample

a large number of samples of size 50 were selected at random from a normal population with mean and variance.The mean and standard error of the sampling distribution of the sample mean were obtain 2500 and 4 respectivly.Find the mean and varince of the population?

Every roll of a fair die has a one in two chance of being even or odd.

This could easily happen with a fair coin after only

There is 2 outcomes for flipping the coin, and 6 outcomes for rolling the cube. The total outcomes for both are 2*6 = 12.

The number of possible outcomes would be 2^6 = 64, since each of the six questions have two possible outcomes.

Because the marble has a higher density than the water does

25

If a random variable X has a Normal distribution with mean m and standard deviation s, then

z = (X - m)/s

has a Standard Normal distribution. That is, Z has a Normal distribution with mean 0 and standard deviation 1.

Probabilities for a general Normal distribution are extremely difficult to obtain but values for the Standard Normal have been calculated numerically and are widely tabulated. The z-transformation is, therefore, used to evaluate probabilities for Normally distributed random variables.

A cube, by definition, must be 6 sided.

The probability of getting a 6, if it is a fair die, is 1/6.

0.0668 or about 1/15

yes

z = ±0.44

The answer depends on the distribution under consideration.

The number of 6s in 37 rolls of a loaded die and binomial.

35

Assuming the coins are fair, two-sided coins, and landing on their sides is not an option, there are four possible outcomes if you consider coin a having a head and coin b having a tail being a different instance from coin a being a tail and coin be having a head. Here they are;

Coin A | Coin B

Heads | Tails

Heads | Heads

Tails....| Heads

Tails....| Tails

There is insufficient information in the question to properly answer it. Please restate the question.