Probability

The probability that a parent carrying a dominant trait will pass that trait on is a 50% chance with each pregnancy

count the number of times you get number 1, when you roll a pair of dice..

cheerio

1 in 6, or about 0.167

To find what z-score represents the 80th percentile, simply solve for 0.8 = F(z), where F(x) is the standard normal cumulative distribution function. Solving gives us:

z = 0.842

never.. the highest number on a dice is a 6

Presuming a standard 52 card deck, you have 5 cards in that deck which satisfy your requirement.

Therefore the probability of getting one of those cards is 5/52.

The mean, median, and mode of a normal distribution are equal; in this case, 22. The standard deviation has no bearing on this question.

The probability is 1 out of two.

The primes you can roll are 2,3, and 5.

If you have a TI-83:

Press [2nd] [DISTR] [3], and then type in ".9, 100, 16)" <- Note the closing parenthesis.

Hit enter and it will give you an answer.

If you have a TI-89:

Press [APPS], then scroll to locate the one called Stats/List Editor (you may only be able to see "Stats/List E". Press [ENTER] to select that app, press [ENTER] again, then press [F5] [2] [1]. For Area, enter .9; for µ, enter 100; and for σ, enter 16. Press [ENTER] again to get your answer.

Hope this helps :).

No. Probability ranges from zero, meaning the event will not happen, to one, meaning the event will happen.

1/4 (25%)

The area under the normal distribution curve represents the probability of an event occurring that is normally distributed. So, the area under the entire normal distribution curve must be 1 (equal to 100%).

For example, if the mean (average) male height is 5'10" then there is a 50% chance that a randomly selected male will have a height that is below or exactly 5'10". This is because the area under the normal curve from the left hand side up to the mean consists of half of the entire area of the normal curve.

This leads us to the definitions of z-scores and standard deviations to represent how far along the normal curve a particular value is. We can calculate the likelihood of the value by finding the area under the normal curve to that point, usually by using a z-score cdf (cumulative density function) utility of a calculator or statistics software.

1/52 or one out of fifty-two

1/16

24

5!/(2!*2!) = 30 ways.

It depends on how many points there are that the spinner can land on. If there are 8, for example, the probability would be 8/16, or 1/2...

8 out of 52

The probability of flipping a quarter and getting heads is 1 in 2. the probability of rolling a die and getting 6 is 1 in 6.

The chance of rolling a 6 twice in a row, on a six-sided die, is 1 in 36 or 2.78%.

The number of possible different results for rolling a six-sided die twice is 6 squared (6 times 6), or 36, therefore the probability of getting any one of the possible results is 1 out of 36.

The probability of drawing a diamond from a standard deck of 52 cards is 13 in 52, or 1 in 4, or 0.25.

It is 1*5C3*(4*3*2*1) = 240

It is 0.017864

4/12