Probability

If you throw a single fair coin multiple times, the probability of getting NO head is:For 1 throw: 1/2

For 2 throws: 1/2 squared = 1/4

For 3 throws: 1/2 cubed = 1/8

etc.

The probability of getting AT LEAST ONE head is the complement; for example, for 3 throws, it would be 1 minus 1/8.

From a scale of 1 to 0 probability measure an event will happen, maybe it will happen or it will not happen.

It is true.

It is the outcome space.

Approx 95% of the observations.

44%

If 4 are available, there are 24 possible ways to assign them. If 7 then there are 840.

That would depend on how many numbers are on the spinner and the cube. The more numbers there are, the less likely it is that they would both land an any given number.

Without knowing the data which is being sampled, it is impossible to answer this other than by saying that the probability is between 0 and 1 inclusive.

Consider a company. If you sample the annual pay of the employees, any mean will be greater than 18 as everyone will be taking home more than £18 per year, so the probability is 1.

Consider a school. If you sample the lengths of feet of the pupils, any mean will be less than 18 as all the feet are less than 18 inches long, so the probability is 0.

Then it is a certainty that the event is 100% to happen.

4/13

As the two events are independent multiply the respective probabilities together:

pr(5) = 1/6

pr(tails) = 1/2*

→ pr(5 and tails) = 1/6 × 1/2 = 1/12

*Actually it is slightly less than 1/2 as there is a very small probability that the coin will end up on its edge; for a small coin it is so small that it can be ignored, but with a scaled up coin it becomes a real possibility as (accidentally) demonstrated in the 1997 Royal Institution Christmas Lecture "The Magical Maze"

The possible prime numbers are 2, 3, 5

The possible numbers greater than 3 are 4, 5, 6

→ a success is 2 3, 4, 5, 6

→ pr(prime or > 3) = 5/6

one in three

1 2 = under 3

3 4 5 6 = at least 3

so 4/6 probability

coin is 1 in 2

4/6 x 1/2 = 4/12 = 1/3

Pr(Both picked 3) = 1/16Pr(Both picked the same) = 1/4.

The answer depends on what the distribution is!

26:52 = 1:2

Assuming you want the probability FOR A SINGLE TRY, and you want the numbers in that exact order, the probability for each part (for instance, first = red; or second = green) is 1/4; therefore, the probability for the combination is (1/4) to the power 4.

Risk

What the answer

If you throw the fair die once then the chances are two as there are two numbers to be shown that is 3 or 5.

Total number of faces and numbers in dice = 6.

So, Probability of two numbers falling = 2/6 = 1/3.

If you roll the same die 180 times then chances of landing on either 3 or 5 = 180 x 1/3 = 60.

You need to ask 1 question at a time, rewording it into 200 characters or less - it helps you to actually think about what is required instead of getting others to do your work for you.

z = (x - µ)/standard deviation

= (52 - 50)/20

= 0.1

(If z is negative it is below the mean.)

This is supposed to be Y > u

There are 45360 ways.