Probability

1 in 27, or 1 in 128, or 0.0078125.

Note: the stated equation is 1 in 27, not 1 in 28, because the question said "same results 8 times in a row". If the question said "heads, 8 times in a row", then the answer would be 1 in 28, but since it said "same results", you have to consider that the second through the eighth flip must match the first flip, and that is 1 in 27.

The sample space is the following set:

{(1. 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),

(2. 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3. 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),

(4. 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),

(5. 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),

(6. 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

The sample space is each card in the deck.

status that aren't mutually exclusive. it refers to person who involve in multiple status. example: some women can be both mother and a businesswoman

No.

When two dies are thrown, there are 36 possible outcomes. The first number represents the outcome of the first die and the second number represents the outcome of the second die.

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)

The probability that a date picked at random is February 30th is zero, as there is no February 30th, even in leap years.

27

Six times the number of different outcomes on the spinner.

The number of permutations of five things taken five at a time is five factorial, or 120.

Large means something or an object that is big in size.

They are both estimates of the probability of outcomes that are of interest. Experimental probabilities are derived by repeating the experiment a large number of times to arrive at these estimates whereas theoretical probabilities are estimates based on a mathematical model based on some assumptions.

if you multiply the number of rolls you did you will get the answer

No, it is not

z = (75 - 85)/5 = -10/5 = -2

no of possibilities

for example tossind a fair coin then

the cardinality of sample space is 2

Mean: 26.33

Median: 29.5

Mode: 10, 35

Standard Deviation: 14.1515

Standard Error: 5.7773

It is 0.0606

z = 0.8416

4/6 = 2/3

There are four different ways that two coins can land:

T T

T H

H T

H H.

Only one of them is two heads, so if the coins are fair, then

the probability is 1/4 = 25% .

They are both measures of the likelihood of specified events.

Because as the sample size increases the Student's t-distribution approaches the standard normal.

There are 52 cards in a deck

there are 4 aces and 4 kings which makes a total of 8 kings and aces.

Assuming that the deck is full and shuffled the probability of drawing an aces or a king is 8/52 which simplifies to 2/13

Assuming that the arrays need to be rectangular, the answer is 14,597,412,049,059,800,000 or approx 15 quintillion.