Probability

These would be independent events; therefore, we can multiply the probabilities of each of the two events.

Probability of flipping a head: 1/2

Probability of rolling an odd number with a single die: 1/6

Required probability : 1/2 x 1/6 = 1/12

There are (10 x 9)/2 = 45 different possible pairs of 2 teachers. For each of these . . .

There are (30 x 29)/2 = 435 different possible pairs of students.

The total number of different committees that can be formed is (45 x 435) = 19,575 .

There are 36 combinations of two dice. each have 1 to 6

To get 10 or more requires 4 +6, 5 +5, 5 +6 , 6+5, 6 +4, or 6+6, which are 6 combinations, leaving 36-6 = 30 combinations of less than 10

30/36 = 5/6 probability of getting sum less than 10

Pr(Z > 0.5) = 0.3085 (approx).

Pr(Z > 0.5) = 0.3085 (approx).

Pr(Z > 0.5) = 0.3085 (approx).

Pr(Z > 0.5) = 0.3085 (approx).

The answer depends on the demography of the population from which the person is randomly selected.

The answer depends on the demography of the population from which the person is randomly selected.

The answer depends on the demography of the population from which the person is randomly selected.

The answer depends on the demography of the population from which the person is randomly selected.

If you are picking a card and putting it back before picking the next, it would be 1/2 * 1/2 * 1/2 * 1/2 = 1/16

If you are not replacing the cards, it would be 26/52 * 25/51 * 24/50 * 23/49 = 358800 / 6497400, or approximately 5.5%.

There are 6 letter in the word crisis so the answer seems to be 6! (6 factorial), but there are two 'i's and two 's's which are indistinguishable and each of which can be arranged in 2! ways. So:

number_of_ways = 6!/2!2!
= 180 ways.

The probability of choosing a blue marble is 5 in 15 or 1 in 3. The probability of then choosing a green marble is 5 in 14. (One is missing) Multiply the two probabilities and you get 5 in 42.(P = 0.1190... about 12%).

Consider the three events:

A = rolling 5, 6, 8 or 9.

B = rolling 7

C = rolling any other number.

Let P be the probability of these events in one roll of a pair of dice.

Then P(A) = P(5) + P(6) + P(8) + P(9) = 18/36 = 1/2

P(B) = P(7) = 6/36 = 1/6

and P(C) = 1 - [P(A) + P(B)] = 1/3

Now P(A before B) = P(A or C followed by A before B)

= P(A) + P(C)*P(A before B)

= 1/2 + 1/3*P(A before B)

That is, P(A before B) = 1/2 + 1/3*P(A before B)

or 2/3*P(A before B) = 1/2

so that P(A before B) = 1/2*3/2 = 3/4

Nonew, since mississipi is not a word!

Nonew, since mississipi is not a word!

Nonew, since mississipi is not a word!

Nonew, since mississipi is not a word!

In a probability sample, each unit has the same probability of being included in the sample. Equivalently, given a sample size, each sample of that size from the population has the same probability of being selected.

This is not true for non-probability sampling.

For discrete distributions, suppose the variable X takes the specific value x with probability P(X=x)

Then add together x * P(X = x) for all possible values of x.

For continuous distributions, suppose the probability distribution function of the variable X is f(x).

Then the mean is the integral of x*f(x) with respect to x, taken over all possible values of x.

Six of them, if the cube is honest (balanced).

Assuming that boys and girls are equally likely, it is 11/16.

The answer depends on where on earth the question is about.

The answer depends on where on earth the question is about.

The answer depends on where on earth the question is about.

The answer depends on where on earth the question is about.

There are three factors of 2 on a regular six-sided die. Therefore, it is 3/6, or 1/2.

The probability of an impossible event is 0.

The probability of an impossible event is 0.

The probability of an impossible event is 0.

The probability of an impossible event is 0.

There are four 7s, which are the 7 of club, 7 of heart, 7 of spade and the 7 of diamond. Each number from 1 to 10 including the Jack, Queen and King have their cards of club, heart, spade and diamond each, which makes 13 (1 to 10 plus J Q and K) x 4 (club, heart, spade and diamond) = 52 cards

1/6

Assume the z-score is relative to zero score. In simple terms, assume that we have 0 < z < z0, where z0 is the arbitrary value.

Then, a negative z-score can be greater than a positive z-score (yes). How? Determine the probability of P(-2 < z < 0) and P(0 < z < 1). Then, by checking the z-value table, you should get:

P(-2 < z < 0) ≈ 0.47725

P(0 < z < 1) ≈ 0.341345

The standard error should decrease as the sample size increases. For larger samples, the standard error is inversely proportional to the square root of the sample size.

The standard error should decrease as the sample size increases. For larger samples, the standard error is inversely proportional to the square root of the sample size.

The standard error should decrease as the sample size increases. For larger samples, the standard error is inversely proportional to the square root of the sample size.

The standard error should decrease as the sample size increases. For larger samples, the standard error is inversely proportional to the square root of the sample size.

stacking the cards in order of face value.....(apex)

Yes, the uniform probability distribution is symmetric about the mode. Draw the sketch of the uniform probability distribution. If we say that the distribution is uniform, then we obtain the same constant for the continuous variable.

* * * * *

The uniform probability distribution is one in which the probability is the same throughout its domain, as stated above. By definition, then, there can be no value (or sub-domain) for which the probability is greater than elsewhere. In other words, a uniform probability distribution has no mode. The mode does not exist.

The distribution cannot, therefore, be symmetric about something that does not exist.