Probability

It is the set of values that a variable can take together with the probability or frequency distribution for those values.

If the pick is completely random, the deck is a standard deck and there are no jokers or any other cards other than the standard 52, the probability is 1/4

The standard deviation is sqrt[n*p*(1-p)] = sqrt(1000*0.94*0.06) = 7.51 approx.

For a continuous variable it is 0.5 but for a discrete variable the answer depends on the probability of the variable taking the mean value. It is half of the rest of the probability.

If the discrete variable X has mean m and Prob(X = m) is p

then Prob(X > m) = (1 - p)/2.

3/52

Assuming you're randomly drawing from a usual deck 52 unique cards. Jack Queen King are the face cards.

There are 6!/(3!*2!) = 60 arrangements.

There are 11880 ways.

It is: 12 out of 50 or 6 out of 25

event B has something in common with event A

Answer: 1/10 for no tickets, 6/10 for two tickets, 3/10 tickets for one ticket.

100%

52 to 1

The months that end in y are January, February, May, and July. Two of those four start with J. So 2/4=.5 is the answer.

Not necessarily.

The probability is 0. If both dice show the number 3 then the sum is 6 which is not odd.

The total probability of something happening plus the probability of that same thing not happening is 1, or 100 %

→ probability of not happening = 1 - 0.25 = 0.75 or 100 % - 25 % = 75 %

Although there are infinitely many primes, they become rarer and rarer so that as the number of numbers increases, the probability that picking one of them at random is a prime number tends to zero*.

In the first 10 numbers there are 4 primes, so the probability of picking one is 4/10 = 2/5 = 0.4

In the first 100 numbers there are 26 primes, so the probability of picking one is 25/100 = 1/4 = 0.25

In the first 1,000 numbers there are 169 primes, so the probability of picking one is 168/1000 = 0.168

In the first 10,000 numbers there are 1,229 primes, so the probability of picking one is 0.1229

In the first 100,000 numbers there are 9592 primes, so the probability of picking one is 0.09592

In the first 1,000,000 numbers there are 78,498 primes, so the probability of picking one is 0.078498

In the first 10,000,000 numbers there are 664,579 primes, so the probability of picking one is 0.0664579

* Given any small value ε less than 1 and greater than 0, it is possible to find a number n such that the probability of picking a prime at random from the numbers 1-n is less than the given small value ε.

It is 0.25

9 x 8 x 7 x 6 x 5

It is 84.3%

1:13

or 4:52

as four suits and one jack in each suit

ww ww

You can expect the spinner to land an odd number 25 times out of 50.

There are no graphs to choose from!