Probability

If she is a 41% shooter she will probably score a goal 41 times out of a hundred, but she will probably miss the other 59 times out of a hundred. So the probability that she will miss is 59 out of 100 = 59% = 0.59

Yes, those events can be found.

If you randomly pick a date in April how many equally likely outcomes are there?

theoretical

Circular systematic sampling is a random sampling method. An example is random sampling of households. Assume that a random number generator provides the number 49 as a starting point. Starting with the household that is 49 on the target list, every nth household on the list would be sampled until the desired sample size is reached

find x

12 - x = 2 x

x = ?

15 + x = 4 x

answers:

1. 4

2. 3

1/12 (1/6 chance of a 5 * 1/2 chance of getting tails)

Is what they are expecting you to know at the end of the course

The subject mathematics needs focus, problem solving ability for which a researcher needs to invest their time. So, they must find a selective PhD topic in mathematics that helps them bring original ideas and research.

Below are a few PhD topic in mathematics subject. If you are looking for the best ideas to help, then these topics will give you a better vision.

• An illustration of mean, mode, and median.
• Mathematical definitions of infinity and how to calculate it.
• Real-life applications of the Pythagorean Theorem.

There are 4 ways to get 3 heads and 1 tail for 4 coin flips. They are: THHH, HTHH, HHTH & HHHT.

The expected number is 3750.

50% or one in two because there are three odd numbers and three even numbers, so the chances of rolling an odd or even number are the same

There are 104, or 10000 permutations of four 10 sided dice.

There is no single word. It is the "probability of that event" (four words).

50/50

3

4

No. Always trust your gut.

You did not have to have exactly two options, but you have nothing to decide if there are not at least two options. However, there are almost always at least two options, although sometimes one of the options is unacceptable. If neither option is reasonable, find a third way.

Assuming you mean when rolling 2 dice, the probability is the number of ways of getting the sum of 5 over the number of possible outcomes.

4 ways of getting 5 (1+4; 2+3; 3+2; 4+1)

36 outcomes (6 x 6)

the probability is 4/36 = 1/9

A computer is programmed to generate a sequence of three digits, where each digit is either 0 or 1, and each of these is equally likely to occur. Construct a sample space that shows all possible three-digit sequences of 0s and 1s and then find the probability that a sequence will contain exactly one 0.

There are 4 possible outcomes yielding an Ace on the third draw without replacement:

a) Ace and Ace (first two cards) then Ace (third card) = 4/52 x 3/51 x 2/50 (24/132600) or

b) Non-ace and Ace then Ace = 48/52 x 4/51 x 3/50 (576/132600) or

c) Ace and Non-ace then Ace = 4/52 x 48/51 x 3/50 (576/132600) or

d) Non-ace and Non-ace then Ace = 48/52 x 47/51 x 4/50 (9024/132600)

Then it's just a+b+c+d

(24+576+576+9024) / 132600

=10200/132600

=0.0769 (about 7.7%)

or more simply 4/52 if you're in a hurry because the oolongteasup

cool and strong