Trigonometry

Trigonometric identities are trigonometric equations that are always true.

SQRT(3)/4 - 1/4

Try and show this as well as you can:

Think of a wheel, or whatever that is cylinder-shaped. One point on the wheel's base is our aim of attention. If you look at the wheel from the side, and roll it at a constant speed, one point on the wheel makes a sine curve.

You could illustrate by adding something that leaves a trail to a cylinder. Like gluing a piece of chalk on a scroll of tape. Then roll the scroll next to a blackboard, and the result should be a sine curve, where the amplitude is the same as the radius of the scroll.

The longest side of the right angles triangle is called the hypotenuse. Divide the length of the side opposite the chosen angle by the length of the hypotenuse. This is the Sine of the angle.

The length of an arc equals he angle (in radians) times the radius. Divide the length by the radius, and that gives you the ange. Measure out the angle on a protractor and draw the length of the radius at the begining and end of the angle. Then draw theportion of the circle with its center at the location ofthe angle and extending out to the radius.

Certainly. A negative angle is simply clockwise instead of counterclockwise from the zero angle, but this is usually not indicated as such on a drawing.

You do not need to, if you have a right triangle that angle is 90* so the other 2 angles are 45* apiece.

That is actually only partially accurate. There can be a right angled triangle with sides of 2-3-5. 5 being the hypotenuse in which the triangle's angles will not be 90-45-45 but 90-33.69-56.31. To find the angles of a right triangle, you will need to know the length of the sides. With the length of all three sides, you will need to utilize sine, cosine, and tangent to find the angles.

A rectangular prism. If every edge is the same length, then it is a cube.

Transform one side into the other, or both sides into a third thing.

A huge practical application of trig is Fourier series. Fourier series says you can represent any periodic function as a sum of infinite sines and cosines. By constructively/destructively overlapping different frequencies with specific amplitudes, you can mimic a function, or signal, or different types of boundary conditions. With more terms, aka more frequencies, you get closer and closer to the actual function.

Fourier series is the only way to solve some types of differential equations. In digital signal processing, fourier series is extremely important because it gives the option of changing a time domain signal into a frequency domain signal. This allows you to manipulate signals in ways one couldn't imagine. Its used in filters, compression, data transmission, etc. The end results affect cell phones, televisions, any kind of digital filter, etc...

Angle B = 2.08 radians (=119.19 degrees).

Let the first odd integer be x, then the second one is x + 2. So we have:

x + (x + 2) = 52

2x + 2 = 52 subtract 2 to both sides

2x = 50 divide by 2 to both sides

x = 25

Thus, the first number is 25. Since consecutive odd integers grow by 2, then the second is 27, the third is 29, the fourth is 31, and the fifth integer is 33.

So the sum of the last two integers is 64 ( 31 + 33).

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SoH: used for finding the sine of a triangle in trigonometry: Opposite/Hypotenuse
CaH: used for finding the cosine of a triangle in trigonometry: Adjacent/Hypotenuse
ToA: used for finding the tangent of a triangle in trigonometry: Opposite/Adjacent

* What are the exponential equivalents of hyperbolics? * How do hyperbolics relate to standard trig functions? * What shape does cosh produce? * Why does cosh grow faster than sinh? * What are the derivatives and integrals of various functions?

You cannot "solve" ungrouped data since ungrouped data is not a question. You can calculate the mean or the variance, standard deviation or skewness, or a whole range of other measures for ungrouped data. But you have not specified what.

sin(0) = 0, sin(90) = 1, sin(180) = 0, sin (270) = -1

cos(0) = 1, cos(90) = 0, cos(180) = -1, cos (270) = 0

tan(0) = 0, tan (180) = 0.

cosec(90) = 1, cosec(270) = -1

sec(0) = 1, sec(180) = -1

cot(90)= 0, cot(270) = 0

The rest of them:

tan(90), tan (270)

cosec(0), cosec(180)

sec(90), sec(270)

cot(0), cot(180)

are not defined since they entail division by zero.

Top left corner

0=45 degrees?

One radian is about 57.3 degrees

Assuming that neither of the given sides is the hypotenuse, then if A is one of the acute angles, tan(A) = 19/63

So A = arctan(19/63) = 16.8 degrees. The other acute angle is 73.2 deg.

The hypotenuse is a side, not an angle. However, if you mean the angle across from the hypotenuse, it is always 90 degrees, or pi/2 radians because hypotenuses only exist in right triangles.

Since theta is in the second quadrant, sin(theta) is positive.

sin2(theta) = 1 - cos2(theta) = 0.803

So sin(theta) = +sqrt(0.803) = 0.896.

x + y = 28 x*y = 7 x=7/y replacing X in eq 1 7/y+y=28 y^2 - 28y + 7 = 0 using above solutions find the reciprocal and sum -- Dhruv

well in order to get sine b you will have to got to your calculator and reverse the equation ... in other words on the calculator you will see sin-1 you will hit that and in the parenthesis you put .96 .so it should look like this sin-1(.96) and you qet your answer .!