Address decoding in the Intel 8085 microprocessor is done by latching the 8 bits of the AD0-AD7 bus during the ALE pulse, holding on the falling edge of ALE. After ALE, the latched results become A0-A7, and the AD0-AD7 bus becomes D0-D7.
As far I know...Intel 8085 isz One address microprocessor.
8085 is a microprocessor designed by Intel
Intel 8085 is a microprocessor that is used in various electronics devices.
8085 is a 8 bit microprocessor designed by Intel Co.
The '8085' in the 8085 microprocessor is the designation given to the microprocessor by Intel. The '5' means it is a single power supply (5 volt) version of the 8080, with enhancements.
+5v supply is alone needed for Intel 8085 Microprocessor
Because that's how Intel designed it. The 8085 is an 8-bit computer operating on a 16-bit address space.
No. The pins are preset by Intel.
5 FLAGS
8 bit input is given to Intel 8085 microprocessor.
Intel AMD only
The Intel 8085 is an 8 bit microprocessor created in 1977.The Intel 8086 is a 16 bit microprocessor created in 1978. The 8086 was the first chip to start the x86 architecture family.8085 contains 16-bit address bus and 8-bit data bus8086 contains 20-bit address bus and 16-bit data bus..In 8085 the clock speed is 3MHZwhere as in 8086 the clock speed is 5MHZ.there are two differences btw 8085&80861. 8086 has 6 byte queue but 8085 has 4 byte queue2. 8086 has 16 bit data bus where as 8085 has 8 bit data bus