You divide your frequency by 1 then divide that answer by the machine cycle. The 8051 uses 12.
So say your frequency is 30MHz you divide that by 1 which gives you 33.3n. then divide that by 12 which equals 2.77nS
ANSWER The Intel 8051 had integrated RAM, ROM, and various I/O functions. This is typical of microcontrollers. I forget the amounts, probably 4 kB of ROM and 64 bytes of RAM? Newer 8051-compatible microcontrollers have a wide variety of memory and integrated I/O options. (Useless information: the 8051 used 12 oscillator cycles per machine instruction cycle, due to the synchronous way it decoded the instructions, fetched the operands, and stored the results. Newer versions get semi-asynchronous and run the same operands in 4, 3, or even 1 cycle.)
the clock oscillator and machine cycle state machine, it may take multiple clock cycles per machine cycle.
an instruction cycle may consist of a number of machine cycles.
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Yes, a washing machine transitions from one cycle to another. There is a water cycle that transitions to a wash cycle, then it transitions to a rinse cycle, a spin cycle and so on.
Intel
how many interrupts in 8051
because i said so thats why
To calculate the length of a cycle, you have to calculate the last day you see your periods and the first day that you see them.
avr is high speed cmpar to 8051.in 8051 there are less number of instructions
8051 - 8 bit micro based on CISC architecture ( Complex Instruction Set Computer) PIC - 8 bit micro based on RISC architecture ( Reduced Instruction Set Computer)AVR - 8 bit micro based on RISC architecture ( Reduced Instruction Set Computer)there are also 16bit and 32 bit micros from the same familyinvention wise, 8051 is the forefather ( date of birth = 1985), next cam PIC s and then came the AVRs.its essential to learn 8051 to be able to learn other micros. if we come to instruction set of these micros :8051 has 250 instructions which take 1 to 4 machine cycles to executivePIC has nearly 40 instructions which are mostly 4 cycles instructionsAVRs have 140 instructions whcih are mostly 1 cycle basedif we come to speed factor:1 machine cycle in 8051 (normal) divides the clock freq. by 12 ( some derivatives divide by 6 and by 1 also)1 machine cycle in PIC divides the clock freq by 41 M.C in AVRs divides the clock freq by 1for eg: if we use 12 Mhz Xtal in all the 3 micros then the speed of execution will be as follows:8051 = 12Mhz /12 = 1 Mhz i,e = 1 million instructions per secondPIC = 12Mhz/4 = 3 Mhz i,e = 3 million instructions per secondAVR = 12Mhz/1 = 12 MHz i,e = 12 Million instructions per second
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