How is demultiplexing done in 8085 microprocessor?

Answer 1

it is nothing

Answer 2

The data bus and the low order address bus on the 8085 microprocessor are multiplexed with each other. This allows 8 pins to be used where 16 would normally be required. The hardware interface is required to demultiplex the bus by latching the low order address in the first T cycle, on the falling edge of ALE.

Answer 3

The address bus is multiplexed in 8085. The multiplexing is done with the help of ALE signal. ALE stands for ''address latch enable''.

When ALE is High (Logic 1) : Upper address lines (line 15-8) and Lower address lines (line 7-0) combinely holds the 16 bits of the address.

When ALE is Low (Logic 0) : Upper address lines (line 15-8) holds the upper 8 bit address & Lower address lines (line 7-0) holds the "8 bit DATA"

Answer 4

Address/data multiplexing is done on the 8085 microprocessor to reduce the number of pins required for the IC. 16 pins are shared by 8, with the overhead of the ALE pin, so this saves 7 pins.

Answer 5

To save pin count on the chip.
The data and address bus are multiplexed in the 8085 to reduce the pin count of the chip. 8 pins are saved, at the cost of one (ALE).

Answer 6

it is nothing