RET instruction needs 3 machine cycles. One to fetch and decode the instruction(4 T states), and two more machine cycles(i.e. 2*3=6 T states) to read two bytes from the stack(stack is exterior to microprocessor, stack is in R/W memory, so to exchange data with stack needs machine cycles). Thus, RET instruction needs total 3 machine cycles and 10 T-states.
when conditional jump instruction is executed it has 10 m/c cycles bt when nt executed it has 7 m/c cycles....while unconditional jump instruction has 10 m/c cycles...
In the 8085 microprocessor, the opcode fetch machine cycle is not sufficient on its own for executing the MOV MA instruction. While the opcode fetch cycle is responsible for retrieving the instruction from memory, additional machine cycles are required to perform the data transfer or execution of the instruction. Specifically, the MOV MA instruction involves both an opcode fetch cycle and a memory access cycle to complete the operation. Therefore, multiple machine cycles are necessary for executing this instruction effectively.
Depending on the particular microprocessor, a machine cycle is the fetch or store of one (typically, one byte) native word. In the 8085, this is a byte fetch or store, plus the overhead in decoding and processing the instruction. In this case, the first machine cycle is four clock cycles, or T states, and subsequent machine cycles are three clock cycles, although certain instruction sequences, such as DAD, require two extra clock cycles.
The instruction IN 84H in the 8085 microprocessor requires 5 machine cycles to complete. This includes 1 opcode fetch cycle and 4 memory read cycles. The opcode fetch retrieves the instruction from memory, while the read cycles are used to read the data from the specified input port.
In the context of the 8085 microprocessor, the ADD instruction takes 1 machine cycle to execute, as it operates directly on the accumulator and the specified register. On the other hand, the LHLD (Load H and L Direct) instruction requires 3 machine cycles, as it involves reading data from a specified memory address into the L and H registers.
The NOP instruction is a no-operation instruction. It does nothing to the state of the machine, except to use some time. In the case of the 8085, it uses four clock cycles plus however many wait states are need to access the NOP instruction from memory.
an instruction cycle may consist of a number of machine cycles.
1 machine cycle for opcode fetch 2nd n 3rd are idle machine cycles as microprocessor is 8 bit therefore it cant perform 16 bit additon in one cycle !!
The timing diagram for the LDA (Load Accumulator Direct) instruction in the 8085 microprocessor involves several key phases. Initially, the opcode is fetched from memory, which takes 4 clock cycles. Next, the address of the data to be loaded into the accumulator is specified in the next two cycles, followed by another two cycles to read the data from the specified memory location into the accumulator. The entire process typically takes 7 machine cycles, including the necessary memory access time.
To calculate the number of machine cycles and opcode fetches for any instruction, you need to refer to the architecture's documentation, which outlines the instruction set and the corresponding cycles for each instruction. Typically, an opcode fetch counts as one machine cycle, and the total machine cycles for an instruction will depend on its complexity and any additional operations it requires, such as data fetches or memory accesses. Analyze the instruction's microarchitecture to determine the number of cycles needed for its execution, including any potential delays or dependencies.
Timing Diagram is a graphical representation. It represents the execution time taken by each instruction in a graphical format. The execution time is represented in T-states.Instruction Cycle:The time required to execute an instruction is called instruction cycle.Machine Cycle:The time required to access the memory or input/output devices is called machine cycle.T-State:The machine cycle and instruction cycle takes multiple clock periods.A portion of an operation carried out in one system clock period is called as T-state.MACHINE CYCLES OF 8085:The 8085 microprocessor has 5 (seven) basic machine cycles. They areOpcode fetch cycle (4T)Memory read cycle (3 T)Memory write cycle (3 T)I/O read cycle (3 T)I/O write cycle (3 T)Each instruction of the 8085 processor consists of one to five machine cycles, i.e., when the 8085 processor executes an instruction, it will execute some of the machine cycles in a specific order.The processor takes a definite time to execute the machine cycles. The time taken by the processor to execute a machine cycle is expressed in T-states.One T-state is equal to the time period of the internal clock signal of the processor.The T-state starts at the falling edge of a clock.
For calculating the T states of the any instruction ,you should know how many machine cycles does the instruction contains and the number of T states in each of the machine cyclesfor example,In a 8085 microprocessor set ,the instr. JMP contains three machine cyclesopcode fetch which is of 4T or 6T statesmemory read which is of 3T statesanother memory read which is again of 3T statesTherefore , the instr. JMP has a total of 10T states