The NOP instruction is a no-operation instruction. It does nothing to the state of the machine, except to use some time. In the case of the 8085, it uses four clock cycles plus however many wait states are need to access the NOP instruction from memory.
The NOP (No Operation) instruction takes time but does nothing to the data or the status of the microprocessor. When executed in a loop, it can take substantial time, from microseconds, to milliseconds, to seconds.
halt,DI (disable intrupts ),EI (enable intrupts),NOP(do nothing)
At a crystal frequency of 6MHz, the 8085 microprocessor has a clock frequency of 3MHz, or a period of 333 nanoseconds. The NOP instruction requires four clock cycles, three to fetch and one to execute, so the NOP instruction with a crystal frequency of 6MHz would take 1.333 microseconds to fetch and execute. This does not include wait states, each of which would add 0.333 microseconds to the timing.
The NOP instruction is short for no-operation. It is an executable instruction that does nothing to the processor, its registers, or its flags. It is useful in timing loops, or to provide room for patchabilty of a piece of code.
it is for a sources enquiry questions and N stands for nature, this is where you describe what type of source it is. O stands for orgin, it is also who produced it, when was it produced and where was it produced. And finally P stands for purpose, this is why was it produced.
no nop nopudy no no no nop nopudy no no
Nop Bophann died in 1959.
NOP means ''Not our Problem'' or ''No Problem''
nop assembly instruction cycle time does differ by the microcontroller type but mostly they don't differ much anyway, I think if i remember well on AVR nop uses 1 cycle, on ARM Cortex M3 nop uses either 2 or 3 cycles depending on several other conditions, PIC uses also 1 clock cycle for its nop instruction but generally all PIC instruction use 4 or even more clock cycle as result of PIC MCU which are non-pipelined and take 4 clock cycles per instruction cycles! for this reason PIC MCU's Oscillator Frequency is always divided by 4 to compensate with the pipelining. this also means that a typical AVR is 4 times faster than PIC. Thus a PIC MCU needs 80 MHz clock to match a typical 20 MHz AVR in terms of speed. ofcourse assuming that both MCU are running exactly the same assembly instructions otherwise if remember well on average PIC's instruction take less cycles than AVR's therefore if both MCU aren't running exact identical assembly program Yes on average AVR will always be faster but probably not exactly twice as much because of some of its instruction taking more cycles than PIC's. I hope the above helps. Nshuti Olivier Massey University - Albany NZ.
Nop Maas was born on December 1, 1949.
nop
It depends on the processor. In the 8086/8088, it means MOV AX,[BX+SI] LODSB In the 8085 it means ADC E NOP XRA H Neither snippet makes any sense, so it must be from some other processor.