An 8 bit processor can transmit one letter at a time. In the ASCII code, each of the first 127 combinations of bits has a special standard meaning. The last 127 is given a special meaning. So an an 8 bit processor can transmit 256 bits at a time. An A is 65 bits.
A 16 bit processor can transmit two letters at a time. A B is 66 bits. An E is 69 bits. It can transmit a B and an E. By definition that is considered a word. A difference exists between the way computer people use the language and normal people use it.
Actually, a piece of equipment called a bus attached to the processor does the actual transmitting.
I have this same question and don't know it, please answer.
Serial ports transmit data one bit at a time, which is why they are becoming obsolete.
there are 1024 words in a 64-bits iterm
It has been offered that: "8000000000 bits are there in 1000Mbps." However, this is not correct. Each M is 1,000,000 bits, so 1,000 M is 1,000 x 1,000,000 or 1,000,000,000 bits per second. Be careful if talking about MBytes of memory, which is 8 times as many bits. Thus, to transmit 1MB of memory at 1 Mbps would take at least 8 seconds (not including protocol overhead and errors requiring retransmission).
512x512x1 (256 = 2^8 = 1byte) * 8 (convert to bits) / 300 bits per second = 6990.50(6) seconds.
address space=24bits => (2 Power 24)=16M words
It requires 6 bits to address 64 words. It does not matter what the word size is.
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A bus with 16 lines can carry 16 bits of data, as each line can transmit one bit. Therefore, the correct answer is d) 16.
The total amount of data (including the start and stop bit) in an 8-bit, 1024× 1024 image, is (1024)2×[8+2] bits. The total time required to transmit this image over a 56K baud link is (512)^2 ×[8+2]/300 =8738.1 sec or about 145.6 min.
Some word processors have a word counter. Some have it in a bar at the bottom of the workspace.
A 32-bit word equals 4 bytes, since there are 8 bits in a byte. Therefore, to convert bits to bytes, you divide the number of bits by 8. So, 32 bits divided by 8 gives you 4 bytes.