In order to interface more than 64K of memory using the 085, you would need an external address register, perhaps maintained by the 8255, which contained an offset register for part of the memory address space. This would be similar to how the 8086/8088 processors implemented expanded memory before using the 80386 and above processors.
Intel 8253 is a programmable timer and it can be interfaced to 8085. This can be used as a real time clock, square wave generator and this is possible because 8253 can create accurate time delays.
we want relay interface with 8085 and also attech the program
In an 8085 system, the memory word size required is 8 bits. This means that each memory location can store 8 bits or one byte of data. The 8085 processor accesses memory locations using these 8-bit memory addresses to read or write data during program execution. The memory word size of 8 bits allows the 8085 system to handle data in small, manageable chunks efficiently.
The 8085 can address 216, or 65536 different memory locations.
explain how slow memory get interfaced with 8085
terminal
READY
The 8085 microprocessor is an 8-bit processor with a 16-bit address bus. This means it can access a maximum of 64 KB (2^16) of memory. The 8085 can address memory locations from 0000H to FFFFH, totaling 64 KB of memory space. This limitation is due to the 16-bit address bus, which can only address up to 64 KB of memory.
The 8085 was replaced with the 8086/8088. As such, there is no 16 bit version of the 8085.
8 bits
64K
Registers or RAM-memory.