ALE is a signal that means that the data bus contains the lower order address bus values. External hardware should strobe the data bus during ALE time, and lock it on the falling edge of ALE.
The 8086 microprocessor has 40 pins.
It is mightily referring to Microprocessor 8086 . I think you saw "8086 microprocessor". The 8086 is nothing it indicates the number of microprocessor same as Digital or analog ic's . 8086 microprocessor has 20 Address buses and 8 data buses which has 1 Mb inbuilt memory for performing several type of airthmatical and logical operation.
queue of 8086 microprocessor is 6 bits
The 8086 Microprocessor operate to require frequency that is provided by clock generator to 8086 Microprocessor and also Synchronization various component of 8086.
it is a 16 bit microprocessor & it has 40 pin .
Pins 1 and 20 in the 8086 microprocessor are (both) power and signal ground (GND).
8086 main application is to evaluate the arithmetic operations in any systems that uses 8086
Which microprocessor accepts the program written for 8086 without any changes?
Two ground pins are used in the 8086 microprocessor to increase the bus pull-down current capacity.
Its 16bit microprocessor,and-> the 8086 has a 16bit databus 20bit address bus-> the intel 8086,is designed to operate in two modes namely(1) minimum mode(2) maximum mode
ya possible
The ALE (Address Latch Enable) signal in the 8086 microprocessor is used to demarcate the time when the address bus is valid. It indicates that the multiplexed address/data bus (AD0-AD15) is carrying a valid address during the first part of a bus cycle. When ALE is asserted, external latches can capture and hold the address, allowing the data bus to later carry data without confusion. This functionality is crucial for enabling the proper interfacing of the 8086 with memory and peripheral devices.