There is insufficient information in the question to properly answer it. You need to specify which FPGA you are interested in. Please restate the question.
yes
The clock out frequency of an 8085 is one half the crystal frequency. The period of one T cycle is the inverse of the clock frequency. At a crystal frequency of 5MHz, the clock is 2.5MHz, and T is 400 ns.
The clock period of a microprocessor is the inverse of its clock frequency. For a clock frequency of 100 MHz, the clock period can be calculated as follows: Clock Period = 1 / Frequency = 1 / 100,000,000 seconds = 10 nanoseconds. Therefore, the clock period is 10 nanoseconds.
If you have the Maximum clock frequency, then you can figure out the minimum clock period using this formula: 1/(minimum clock period) = (Maximum clock frequency).
How to make Low frequency clock generator using ANAD gates?
The clock period is the time duration of one clock cycle. For a clock frequency of 1 GHz (1 billion hertz), the clock period would be 1 nanosecond (1/1,000,000,000 seconds).
The clock period is calculated as the inverse of the clock frequency. It can be determined using the formula: [ \text{Clock Period} (T) = \frac{1}{\text{Clock Frequency} (f)} ] For example, if the clock frequency is 2 GHz, the clock period would be ( T = \frac{1}{2 \times 10^9} = 0.5 ) nanoseconds.
that depends on the microcontroller. check the datasheet.
We use clock signal in timing diagram because the microprocessor operates with reference to clock signals provided to it. At pins X1 and X2 we provide clock signals and this frequency is divided by two. This frequency is called as the operating frequency.
Yes, FPGA is used in some ways in mobiles.
The 555 IC timer does not have a clock.
FPGA is sutiable for complicated arch than CPLD. CPLD is very tiny when compared to the logic of FPGA so CPLD is faster.