memory interfacing in 8085 microprocessor refers to provide a intermediate mode of transferring or receiving data from registers to main memory
In the 8085 microprocessor, memory-mapped I/O uses the same address space for both memory and I/O devices, allowing up to 64 KB of I/O addresses. In contrast, I/O mapped I/O (also known as port-mapped I/O) utilizes a separate address space for I/O operations, which allows for a limited number of I/O devices to be addressed (up to 256 8-bit ports). The instructions for accessing memory-mapped I/O involve standard memory instructions (like MOV), whereas I/O mapped I/O requires specific instructions like IN and OUT. This distinction affects how devices are interfaced and programmed.
Yes, the 8085 microprocessor can access memory location A000, as it has a 16-bit address bus that allows it to address up to 64KB of memory, ranging from 0000 to FFFF in hexadecimal. The address A000 falls within this range, meaning the 8085 can read from or write to this memory location. However, the actual access depends on the system's memory configuration and whether that specific address is mapped to valid RAM or ROM.
rom values are permanent and we cant change its value.....we can only read but cant write it
A memory mapped register is a register that has its specific address stored in a known memory location.
The 8085 microprocessor is an 8-bit processor with a 16-bit address bus. This means it can access a maximum of 64 KB (2^16) of memory. The 8085 can address memory locations from 0000H to FFFFH, totaling 64 KB of memory space. This limitation is due to the 16-bit address bus, which can only address up to 64 KB of memory.
Memory mapped IO is one where the processor and the IO device share the same memory location(memory) while IO mapped IO is one where the processor and the IO device have different memory located to each other.
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The 8085 can address 216, or 65536 different memory locations.
explain how slow memory get interfaced with 8085
Memory mapped buses helps in the extension of the address of the physical ram through which the devices can access the address
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In an 8085 system, the memory word size required is 8 bits. This means that each memory location can store 8 bits or one byte of data. The 8085 processor accesses memory locations using these 8-bit memory addresses to read or write data during program execution. The memory word size of 8 bits allows the 8085 system to handle data in small, manageable chunks efficiently.