mov
•The mov instruction carries out assignment in 8086 assembly language. •It which allows us place a number in a register or in a memory location (a variable) i.e. it assigns a value to a register or variable. Example: Store the ASCII code for the letter A in register bx.•A has ASCII code 65D (01000001B, 41H) •The following mov instruction carries out the task:•mov bx, 65d•We could also write it as:•mov bx, 41h•or mov bx, 01000001b•or mov bx, 'A'
mov r1r2 is invalid instruction because of there is no communication with ALU in its operation;
In 8086 the instruction queue is 6 byte long. This is because even the longest 8086 instruction is 6 byte long. Thus it is possible to prefetch even the longest instruction in the instruction set.
i.e.-->mov ax,2000h (in 8086)
Mov ax,1234 mov bx,2345 add ax,bx mov @(some memory location ) say 2200,ax hlt
mov H , L mov is opcode H L are operands
Mov ax,[2020h] mov bx,[2022h] mul bl mov [2024h],ax hlt
IRET
mov si,1300;source mov di.1500;destination mov ch,05;limit lo: mov al.[si] mov [di],al inc si inc di dec ch jnz lo
Code segment assume cs:code mov si,1500h mov di,1600h mov ax,[si] mov bx,[si+2] add ax,bx mov [di],ax mov [di+2],dx mov ah,4ch int 21h code ends end
The Instruction Pointer (IP) in an 8086 microprocessor contains the address of the next instruction to be executed. The processor uses IP to request memory data from the Bus Interface Unit, and then increments it by the size of the instruction.