IRET
When the 8086 microprocessor receives an interrupt signal, it completes the execution of the current instruction and saves the address of the next instruction onto the stack. It then determines the appropriate interrupt vector from the Interrupt Vector Table (IVT) based on the interrupt type. The processor then transfers control to the interrupt service routine (ISR) associated with that interrupt. After the ISR has executed, the 8086 retrieves the saved address from the stack and resumes execution from where it was interrupted.
In 8086 the instruction queue is 6 byte long. This is because even the longest 8086 instruction is 6 byte long. Thus it is possible to prefetch even the longest instruction in the instruction set.
The Instruction Pointer (IP) in an 8086 microprocessor contains the address of the next instruction to be executed. The processor uses IP to request memory data from the Bus Interface Unit, and then increments it by the size of the instruction.
6 bytes
6 bytes
in 8086, there is instruction queue of 6 byte. It is one of the reason behind giving name. 8086 was introducing pipeline architecture.
mov
Yes.
There is no PC register in the 8086/8088. It is called the IP register by Intel and it stands for the Instruction Pointer. It contains the address of the current/next instruction to be executed.
In the 8086 microprocessor, the maximum length of an instruction is 6 bytes. This includes the opcode, any necessary prefixes, and operands. The architecture allows for complex addressing modes, which can contribute to the instruction length, but the limit remains at 6 bytes for any single instruction.
Its role is to point to the next instruction to be executed in the CPU. It always points to the next instruction to be executed in the CPU
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