6 bytes
In 8086 the instruction queue is 6 byte long. This is because even the longest 8086 instruction is 6 byte long. Thus it is possible to prefetch even the longest instruction in the instruction set.
6 bytes
pata nai
in 8086, there is instruction queue of 6 byte. It is one of the reason behind giving name. 8086 was introducing pipeline architecture.
queue of 8086 microprocessor is 6 bits
In the 8086 microprocessor, the maximum length of an instruction is 6 bytes. This includes the opcode, any necessary prefixes, and operands. The architecture allows for complex addressing modes, which can contribute to the instruction length, but the limit remains at 6 bytes for any single instruction.
increases speed
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An instruction queue is used in the 8086 to speed up the average time it takes to process an instruction. Some instructions are faster than the bus, while some are slower. If the CPU had to wait for all of the instructions, there would be gaps of time where the CPU is doing nothing. The queue helps to eliminate that gap by prefetching instructions in the hope that they will be ready for use when the CPU gets to them.
Maybe you mean the prefetch queue?
8086 is a small 4 or 6 byte instruction cache or queue that perfetched a few instructions before they were executed. In addition, the 8086 addressed 1M byte of memory, which is 16 times more than 8085. N.K.Jha narayankumarjha2010@gmail.com
The 8086/8088 instruction queue is a buffer that holds opcode bytes that have been prefetched by the bus interface unit. This speeds up operations of the processor by helping to reduce fetch latency, i.e. to improve the probability that an opcode byte fetched by the processor is already available.