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In the 8086 microprocessor, the maximum length of an instruction is 6 bytes. This includes the opcode, any necessary prefixes, and operands. The architecture allows for complex addressing modes, which can contribute to the instruction length, but the limit remains at 6 bytes for any single instruction.
6 bytes
increases speed
Header is always a multiple of 4bytes and so we can have a maximum length of the field as 15, so maximum size of the header is 60 bytes out of which 20 bytes are mandatory.
Word length.
There are 74 instructions in the 8085 microprocessor.
1518 bytes
A 64-bit microprocessor can theoretically address 2^64 bytes of memory, which equals 16 exabytes. However, in this case, the instruction format specifies that the first 2 bytes are for the opcode, leaving 62 bits for the operand address. Therefore, the maximum directly addressable memory capacity is 2^62 bytes, which equals 4 petabytes.
The datagram length field in an IP header is 16 bits in length. Therefore, the maximum datagram size an IP datagram can support is 2^16 - 1 = 65,535 bytes
6 bytes
The minimum size of an Ethernet frame is 64 bytes. Even if the VLAN tag is 4 bytes, the Ethernet frame with VLAN tagging remains 64 bytes.
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