In the context of the 8086 microprocessor, the prefetch queue is a 6-byte high-speed queue that stores the next instruction to be executed. This helps improve performance by fetching instructions in advance and storing them in the queue. When the CPU is ready to execute the next instruction, it can quickly access it from the prefetch queue without having to wait for the instruction to be fetched from memory.
Maybe you mean the prefetch queue?
In 8086 the instruction queue is 6 byte long. This is because even the longest 8086 instruction is 6 byte long. Thus it is possible to prefetch even the longest instruction in the instruction set.
queue of 8086 microprocessor is 6 bits
6 bytes
6 bytes
Because that's how Intel designed it. They chose a 6 byte queue in the 8086 in order to optimize speed versus latency of the execution unit versus the bus interface unit. The decision for 6 bytes, as compared to 4 or 8 or some other number was a cost tradeoff and a recognition of the average mix of instruction execution cycle times in a typical processing thread.
in 8086, there is instruction queue of 6 byte. It is one of the reason behind giving name. 8086 was introducing pipeline architecture.
The instruction prefetch queue speeds up the processing of microprocessors by attempting to have the next opcode bytes available to the execution unit before it actually needs them. This works because, statistically, there is time spent by the execution unit in executing a particular instruction; time that the bus interface unit can use to go ahead and prefetch the next opcode bytes. Sometimes, this results in a loss of time, because the execution unit may branch to some other location. Modern processors attempt to sidestep that by using branch prediction algorithms.
An instruction queue is used in the 8086 to speed up the average time it takes to process an instruction. Some instructions are faster than the bus, while some are slower. If the CPU had to wait for all of the instructions, there would be gaps of time where the CPU is doing nothing. The queue helps to eliminate that gap by prefetching instructions in the hope that they will be ready for use when the CPU gets to them.
The 8086/8088 instruction queue is a buffer that holds opcode bytes that have been prefetched by the bus interface unit. This speeds up operations of the processor by helping to reduce fetch latency, i.e. to improve the probability that an opcode byte fetched by the processor is already available.
8086 is a small 4 or 6 byte instruction cache or queue that perfetched a few instructions before they were executed. In addition, the 8086 addressed 1M byte of memory, which is 16 times more than 8085. N.K.Jha narayankumarjha2010@gmail.com
In terms of computer language a pipeline is a set of data elements which are combined together and the yield or output of one element is taken as input for the other. In an 8086 microprocessor a bus used to execute data with help of 6-byte prefetch que.