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How do you calculate number of address lines needeed for 1 MB?
20 address lines are required
How many address lines required in 1gb?
To determine the number of address lines required for 1 GB of memory, we can use the formula (2^n = \text{Memory Size}), where (n) is the number of address lines. Since 1 GB equals (2^{30}) bytes, we need (30) address lines to uniquely address each byte in 1 GB of memory. Therefore, (30) address lines are required for 1 GB.
How many address lines are needed to access 256KB of main memory?
The number of address lines needed to access N-KB is given by log2N Then the number of address lines needed to access 256KB of main memory will be log2256000=18 address lines.
How many no of address lines required in 64kB memory?
To calculate the number of address lines required for a 64 kB memory, first convert 64 kB into bytes: 64 kB = 64 × 1024 bytes = 65,536 bytes. The number of address lines needed can be determined using the formula (2^n = \text{total number of addresses}), where (n) is the number of address lines. Since 65,536 is (2^{16}), you need 16 address lines to address a 64 kB memory.
How many address lines would be required for a 2K?
In the 2k*16 , the 11 address lines are required and the 16 input-output lines are required..
How many nuMBer of address lines required for 8 MB of memory?
It takes 23 address lines to address 8 mb of memory.
How many no of address lines required in 1MB memory 111622 or 24?
How many no of address lines required in 1MB memory 11,16,22 or 24 u haven't specified correct options! 20 address lines will be required because 1 MB is 1024 KB that is 1024*1024 Byte which is equivalent to (2^10)^2 bytes if ur memory is Byte addressable then address lines required will be 20.
How many address line required for 10 kb data?
To determine the number of address lines required for 10 KB of data, we first convert 10 KB into bytes, which is 10,240 bytes (since 1 KB = 1,024 bytes). The number of addressable locations is equal to the number of bytes, and to find the number of address lines needed, we can use the formula (2^n \geq \text{number of bytes}). Solving (2^n \geq 10,240), we find that (n) must be at least 14, as (2^{14} = 16,384) is the smallest power of 2 that exceeds 10,240. Therefore, 14 address lines are required.
How many address lines and data lines are required for a2Kx8 memory?
A 2K X 8 memory requires 11 address lines and 8 data lines
How many address lines are required if micro processor has to access 2kb memory?
2kb=2*1024=2048 2^11=2048 therefore 11 address lines are required
How many address lines and data lines are required for a 128k x 8 memory system?
17 address lines and 8 data lines. 2^17=128k
How many nuMBer of address lines required for 1 MB memory?
Firstly we need to convert Mb's into bits i.e 1Mb=1024x1024 = 210x210 =220 That means there are 220 memory locations and we will need 20 address lines.
