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It takes one address line to choose between two modules.

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13y ago

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How do you calculate number of address lines needeed for 1 MB?

20 address lines are required


How many address lines are needed to access 256KB of main memory?

The number of address lines needed to access N-KB is given by log2N Then the number of address lines needed to access 256KB of main memory will be log2256000=18 address lines.


How many address lines would be required for a 2K?

In the 2k*16 , the 11 address lines are required and the 16 input-output lines are required..


How many nuMBer of address lines required for 8 MB of memory?

It takes 23 address lines to address 8 mb of memory.


How many no of address lines required in 1MB memory 111622 or 24?

How many no of address lines required in 1MB memory 11,16,22 or 24 u haven't specified correct options! 20 address lines will be required because 1 MB is 1024 KB that is 1024*1024 Byte which is equivalent to (2^10)^2 bytes if ur memory is Byte addressable then address lines required will be 20.


How many address lines and data lines are required for a2Kx8 memory?

A 2K X 8 memory requires 11 address lines and 8 data lines


How many address lines and data lines are required for a 128k x 8 memory system?

17 address lines and 8 data lines. 2^17=128k


How many address lines are required if micro processor has to access 2kb memory?

2kb=2*1024=2048 2^11=2048 therefore 11 address lines are required


How many nuMBer of address lines required for 1 MB memory?

Firstly we need to convert Mb's into bits i.e 1Mb=1024x1024 = 210x210 =220 That means there are 220 memory locations and we will need 20 address lines.


How many no of address lines are required for 512 K word memory?

If you are addressing bytes, then 512K words (16 bit words) requires 20 address lines.I gave that answer because the question was categorized 8086/8088. If you are addressing words, then the answer is 19 address lines.


How many address lines and data lines are required from 256K 16 memory system?

In a 256K x 16 memory system, the memory has 256K (256 * 1024 = 262,144) addressable locations and each location holds 16 bits of data. To calculate the number of address lines needed, we find the base-2 logarithm of 256K, which is 18 (since 2^18 = 262,144). For the data lines, since each location holds 16 bits, 16 data lines are required. Thus, the system requires 18 address lines and 16 data lines.


How many address lines are required for 1 kilobyte of ram?

10. 210 = 1024.