With the restrictions specified in your question, there are 8 x 2 x 10 = 160 possible area codes.
However, those restrictions do not match the restrictions on actual area codes in North America (USA, Canada, etc.). North American area codes have the first digit not 0 or 1, the second digit not 9, and the third digit not the same as the second digit (such codes are reserved for special purposes like toll-free), leaving 8 x 9 x 9 = 648 possible area codes.
The number of 3-digit numbers with no repeated digits is simply 10x9x8 = 720, if you allow, for example, 012 as a 3-digit number. There are 10 digits, any of which might be the first digit. The second digit can be any digit except the digit that was used for the first digit, leaving 9 possibilities. The third digit then has 8 possibilities, since it can't be the same as the first or second digit. The actual number of possible area codes will be lower, because there are additional restrictions on the number combinations for a valid area code. For example, in North America (USA, Canada, etc.), the first digit of an area code cannot be 0 or 1 and the middle digit cannot be 9.
first digit time second digit and second digit times first digit then repeat
Not necessarily. Consider 444. The digits are not different. The first and second digits are not multiples of 3 The first digit is not greater than the second digit. In spite of all that, 444 is a 3-digit number
No, you cannot use an OBD scan tool. The DRB2 connection you are referring to can be used by a mechanic with the proper tools. You can read the codes by the key method. Turn the key on, then off, then on, then off, and finish with on. The codes will then flash the number of the first digit then it will pause and blink the number of the second digit.
For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.For the first digit you have 5 options, whichever you choose for the first digit, you have 4 options for the second digit, etc.; so the number of combinations is 5 x 4 x 3 x 2.
There are 26 choices for the first letter, 25 choices for the second letter (since we can't repeat the first letter), and 10 choices for the digit. Therefore, the total number of possible codes is: 26 x 25 x 10 = 6,500 So there are 6,500 possible codes with 2 letters and one digit if no letter or digit appears more than once.
If the second digit is 1, 2, 3 or 4 replace it by 0. If the second digit is 6, 7, 8 or 9 replace it by 0 and increase the first digit by 1. If the second digit is 5, then, if the first digit is even, replace the second digit by 0, if the first digit is odd, replace the second digit by 0 and increase the first digit by 1. Many people will require that 5 as the second digit should be treated the same as 1-4. This ignores the upward bias introduced and IEEE 754 standard for rounding.
1349
208
Look for the first digit that is different. In this case, the first digit after the decimal point. The number that has the larger digit in this position, is larger. If the first digit is the same, compare the second digit with the second digit, the third digit with the third digit, and so forth, until you find a difference.
182
Please compare the first digit after the decimal point with the first digit. If they are equal, compare the second digit with the second digit, etc. 0.1 is equivalent to 0.100.