The lower the number the better. -40 to -30 is good
Edit
well the lower would be the other way, the closer to 0 is the best
-100 is just barely a signal and - 40 is the best you can get
well the wifi meter i have is -100 to -40
-60 & -40 between them numbers its a great signal
wet mix mecadam is a base layer of DBM bonding b/w WMM and DBM is too good and we can compact the WMM fully..........
20 dbm
Yes, DBM (data base management) is real.
P(dBm) = 10log10(10mW) = 10dBm
dBw=dBm-30 then 75-30=45 dBw dBw=dBm-30 then 75-30=45 dBw dBw=dBm-30 then 75-30=45 dBw
DBM outplacement information can be located directly on the DBM website. You can also locate this type of information on career transition websites as well.
Mic level is -56 to -40 dbm. Line level is either -10 dbm or 4 dbm. You need a preamp to amplify a microphone to line level.
Gain = Pout - Pin = -10dBm - (-5dBm) = -5dB
The decibel-milliwatt (dBm) scale is a logarithmic unit used to express power levels relative to 1 milliwatt (mW). Specifically, 0 dBm is defined as the power level equal to 1 mW. Therefore, when the power is exactly 1 mW, it translates to 0 dBm, as dBm is calculated using the formula ( \text{dBm} = 10 \times \log_{10}(\text{Power in mW}) ); thus, ( \log_{10}(1) = 0 ), resulting in 0 dBm.
To convert dBm (decibels relative to 1 milliwatt) to dB (decibels), you can use the formula: ( \text{dB} = \text{dBm} - 30 ). This is because 0 dBm corresponds to 1 milliwatt, and dB represents a ratio relative to 1 watt. Therefore, subtracting 30 adjusts the dBm value to reflect a comparison to 1 watt instead of 1 milliwatt.
The density of a typical dense-graded base mix (DBM) layer for road construction ranges from 110-140 pounds per cubic foot (pcf) or 1,760-2,240 kilograms per cubic meter (kg/m³). This density provides the necessary strength and stability for the road base. It is important to consult project specifications and guidelines for the specific density requirements of the DBM layer being used.
The 'm' in dBm means the power is referenced to 1mW. So, the power in dBm equals 10 times the log of the power in mW, or P(dBm) = 10*log(P(mW)/1mW). For example, 1W = 1000mW, so 10*log(1000/1) = 30dBm.