Suppose we give a 8-bit instruction ADD B to the microprocessor then this instruction is not at all understood by microprocessor as it only accepts binary inputs so first of all it stores the instruction in the INSTRUCTION REGISTOR then it decodes this instruction ADD B to its suitable binary code 80H in the INSTRUCTION DECODER.. after converting to 80H then the microprocessor understands that .. yes i have to add the content of the resistor B with that of A(accumulator) and store the result in the accumulator A this is a small example how microprocessor operates facing the instructions
To add a new machine language instruction to an processor instruction set, you need to replace the microcode of the processor.
add B
That would depend on the computer architecture.
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this instruction is used to add the specified register content to that of the accumulator along with the carry flag value. this instruction is used in processes which involve continuous addition.
Yes. Anyone can add, edit or delete flags.
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Oh, what a happy little question! To add the two hexadecimal numbers 3AH and 48H using the ADI instruction, you can first load 3AH into the accumulator, then use the ADI 48H instruction to add 48H to the accumulator. Finally, you can store the result in memory location 2100H. Just remember to take your time, enjoy the process, and trust in your abilities to create something wonderful!
No. Check the instruction guide.
At a clock frequency of 5 MHz (10 MHz crystal) the 8085 has a clock period of 200 ns. An instruction using 18 cycles would use 3.6 us. (Microseconds)This is for the case with no wait states. Each wait state adds 200 ns. Since an 18 cycle instruction has 5 memory accesses, one wait state per access would add 1 us to the execution time.
At a clock frequency of 5 MHz (10 MHz crystal) the 8085 has a clock period of 200 ns. An instruction using 18 cycles would use 3.6 us. (Microseconds)This is for the case with no wait states. Each wait state adds 200 ns. Since an 18 cycle instruction has 5 memory accesses, one wait state per access would add 1 us to the execution time.