4409 HoBN in F refers to the chemical compound Holmium Boron Nitride, which contains holmium (Ho), boron (B), and nitrogen (N). This compound is notable for its potential applications in advanced materials, particularly in high-temperature and electronic devices. The "F" could denote a specific context or format, such as a formula or classification, but further clarification would be needed for a definitive interpretation.
ITS EASY...TRY THIS OUT..TRAPEZOIDAL METHOD#include#include#includefloat valcal(float x){return (x*x*x);}int main(){float a,b,h,c,I;int n,i;printf("THE TRAPEZOIDAL RULE:\n");printf("---------------------");printf("\n\n\nEnter the two limits and the no. of divisions:\n");scanf("%f %f %d",&a, &b, &n);h=(b-a)/n;//printf("\nVALUE of h: %f\n", h);c=a;I=valcal(a)+valcal(b);//printf("\nVALUE FOR a: %f\n", valcal(a));//printf("\nVALUE FOR b: %f\n", valcal(b));for(i=1;i=b){printf("\n\nc>b\n\n");break;}//printf("\nVALUE FOR %f: is %f\n",c, valcal(c));I=I+(2*valcal(c));//printf("\nI right now is %f", I);}printf("\n\n\nThe integration of x*x*x is: %f",(h*I)/2);printf("\n\n\n");system("pause");}SIMPSON'S 1/3RD METHOD#include#include#includefloat valcal(float x){return (1/(1+x*x));}int main(){float a,b,h,c,I;int n,i;printf("THE SIMPSON'S ONE-THIRD RULE:\n");printf("------------------------------");printf("\n\n\nEnter the two limits and the no. of divisions:\n");scanf("%f %f %d",&a, &b, &n);h=(b-a)/n;//printf("\nVALUE of h: %f\n", h);c=a;I=valcal(a)+valcal(b);//printf("\nVALUE FOR a: %f\n", valcal(a));//printf("\nVALUE FOR b: %f\n", valcal(b));for(i=1;ib){printf("\n\nc>b\n\n");break;}//printf("\nVALUE FOR %f: is %f\n",c, valcal(c));if(i%2==0)I=I+(2*valcal(c));elseI=I+4*valcal(c);//printf("\nI right now is %f", I);}printf("\n\n\nThe integration of x*x*x is: %f",(h*I)/3);printf("\n\n\n");system("pause");}NEED MORE HELP...MAIL ME YOUR PROB... SEE YA
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#include<stdio.h> #include<conio.h> #include<math.h> float f(float x) { float y; if(x!=0) //y=sin(x)-log(x)+exp(x); y=1/(1+x); else printf("answer can not be derived"); return(y); } float g(float x) { float k; k=(-2)/(pow((1+x),3)); return(k); } void main() { float i,n,k,z,s=0,err=0; float h,x,a[100],b,c; clrscr(); printf("\n enter the range of the integration"); scanf("%f%f",&b,&c); printf("\n enter n so to divide the range into n parts"); scanf("%f",&n); h=(c-b)/n; printf("\n\n%f",h); k=(f(b)+f(c)); printf("\nk=%f\n\n",k); for(i=b+h;i<c;i+=h) { z+=f(i); printf("\n%f",z); } s=(h*(k+2*z))/2; printf("\n\n the value of the integration=%f\n\n",s); for(i=b;i<=c;i+=h) err+=g(i); err=(err*(pow(h,3)))/12; printf("\n\n approximate error= %f\n\n",err); getch(); }here...
a b c d e f g h i j k l m n OOOOOOOOOOOOOOO a b c d e f g h i j k l m n OOOOOOOOOOOOOOO
#include<stdio.h> #include<conio.h> #include<math.h> #define f(x) (sin(x*x)) void main() { float a,b,h,x,s,n,aaa,h1,h2,p=0.0,p1=0.0,pp,sum,k,i=0.0; int j=1,co; clrscr(); printf("\n Plese Enter lower limit :"); scanf("%f",&a); printf("\n Plese Enter upper limit :"); scanf("%f",&b); printf("\n Plese Enter the number of Intervales::"); scanf("%f",&n); h=(b-a)/n; //Calculiting the value of h printf("The ..................=%f",h); x=a+h; s=f(a)+f(b); //Calculiting the First term & last term while(j<n) { if((j%2)==0) //checking even and odd terms i=i+(2*f(x)); //Calculiting the even terms else i=i+(4*f(x)); //Calculiting the odd terms x=x+h; j++; } i=(h/3)*(i+s); //putting all data in to the formula printf("\nThe value of the integral is %f",i); // part is for Error calculation h1=b-h; h2=a+h; pp=(7*(f(h2)+f(h1))); sum=a-h; k=b+h; x=a+(2*h); for(co=2;co<n-2;co++) { if(co%2==0) p=p+(f(x)); else p1=p1+(f(x)); x=x+h; } aaa=(-(h/90))*( ( f(sum)+f(k) )-4*(s) +7*( f(h1) )-(8*p)+(8*p1) ); printf("\nThe Error is= %f",aaa); getch(); }
#include<stdio.h> #include<conio.h> int main(void) { float a,b,c=0, d=0, e=0,f=0; printf("Please enter two numbers:\n"); scanf("%f %f", &a, &b); c=a+b; d=a-b; e=a*b; f=a/b; printf("The sum of %f and %f is :%f\n", a,b,c); printf("The subtraction of %f and %f is :%f\n", a,b,d); printf("The multiplication of %f and %f is :%f\n", a,b,e); printf("The division of %f by %f is :%f\n",a,b,f); getch(); }
B, D, E, F, H, I, K, L, M, N, P, R, T, (As capitals) b, d, h, i, k, l, m, n, p, q, r, (as small letters)
The only English word is rhythm.
Some words that you can make with H V N N R F Q O are:hornforfrohononorofohonor
The bond stretching frequency increases with increasing bond strength. Therefore, the order of increasing bond stretching frequency is: F-H < O-H < N-H < C-H.
The quotient rule tells says that: If: f(x) = g(x) / h(x) Then: f'(x) = (g'(x) · h(x) - g(x) · h'(x)) / h(x)2 That derivative gives you the slope of the original curve's tangent at any given x-coordinate. For example, if: f(x) = axn / bxm then: f'(x) = (anxn-1 · bxm - axn · bmxm - 1) / b2x2m This of course simplifies considerably, due to the simplicity of the original function: = (abnxm+n-1 - abmxm+n-1) / b2x2m = (n - m)abxm+n-1 / b2x2m = (n - m)axn-m-1 / b = (n - m)(a/b)xn-m-1 Which makes perfect sense if you rearrange our initial function and take it's derivative in a simpler manner: f(x) = axn / bxm f(x) = (a/b)xn-m f'(x) = (n-m)(a/b)xn-m-1
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern B-N-F-SH. That is, eight letter words with 1st letter B and 3rd letter N and 5th letter F and 7th letter S and 8th letter H. In alphabetical order, they are: bonefish