2 slices of bread to make a sandwich.
B
The rate of the reaction is determined by the rate law, which is typically expressed as Rate = k[A]^m[B]^n, where m and n are the orders of the reactants. If k = 3, A = 2 M, and B = 2 M, and the reaction is kA^2B, then the rate would be 3 x (2)^2 x (2) = 24 M/s.
M. B. S. E. M. M. has written: 'The mi---st---l light'
RS 530 has a logarithmic degradation on cable length as the data signaling rate increases. These are some of the readings on the chart: up to 90k b/s - 1.2k meters.....400k b/s - 300 meters....1.2 M b/s - 100 meters approx......2 M b/s - 40 meters....6 M b/s - 20 meters...10 M b/s - approx 15 meters....
0.4 (mol/L)/s
Formula: S=1/2 bh S - area, b - base, h - height S= 1/2 * 11* 23= 126.5
The correct answer is B: 9.8 m/s downward. In free fall near the surface of the Earth, objects accelerate at a rate of 9.8 m/s^2 downwards due to gravity. After 0.10 seconds, the object's velocity would be 9.8 m/s downward.
The rate law for this reaction is rate = k[A]^m[B]^n. From the given information, substituting the values for rate, [A], [B], and the exponents m and n, you can solve for the rate constant k. In this case, k = rate / ([A]^m[B]^n), so k = 2 / (10^2 * 3^1).
0.5
The third side must be 18 m. (It cannot be 2.25 m because then the two equal sides would sum to 4.5 m which is less than the third.) Denote the 3 sides by a, b and c and let s = (a+b+c)/2 = 19.125 m Then area = sqrt[s*(s-a)*(s-b)*(s-c)] = 20.21 m2 approx.
.72 (mol/L)/s
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