two heads are better than one
2 humps on a Bactrian Camel.
Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)
2 Humps on a Bactrian Camel (just one on a dromedary).
2 Humps on a Bactrian Camel (just one on a dromedary).
The area of a trapezoid is equal to (1/2)(B + b)h]. In our case B = 10 ft, b = 8 ft, and h = 5 ft, So A = (1/2)(B + b)h = (1/2)(10 + 8)(5) = 45 ft^2
A=area b=base h=height A=1/2*b*h
Square: b*h Triangle:1/2 b*h *** means multiply**
Elliptical Fuel Tank Calculation V=(a/2*b/2*ACOS(1-h/b*2)-a/2*(b/2-h)*SQRT(1-(1-h/b*2)^2))*L V=Volume a=major ellipse axis b=minor ellipse Axis h=height of liquid L=tank lenght or you can use calculator online on : See related links
A=30, B=15, H=4 A=30, B=12, H=5 A=30, B=2, H=30 1/2 b x h= Area
A=h(b+B) divided by 2 * * * * * where A = area h = vertical height b and B are the lengths of the parallel sides.
1/2(b)(h) = 1/2(base)(height)
In the standard equation of an ellipse, ( \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1 ), the variable ( b ) represents the semi-minor axis length of the ellipse. Here, ( (h, k) ) is the center of the ellipse, ( a ) is the length of the semi-major axis, and ( b ) is the length of the semi-minor axis. If ( a > b ), the ellipse is elongated along the x-axis; if ( b > a ), it is elongated along the y-axis.