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Well, darling, "9 J on the S C" is simply code for "9 Jacks on the Suit of Clubs." So, in a standard deck of cards, it means there are 9 Jacks in the Clubs suit. But hey, if you're not into card games, feel free to use that knowledge to impress your friends at your next game night.
What else can I help you with?
What does 9 j in the s c mean?
"9 J in the S C" commonly refers to the phrase "9 justices in the Supreme Court," referencing the total number of judges on the highest court in the United States.
9 j of the s c?
9 justices on the supreme court
What is 9 j on the you s s c?
9 judges on the united states supreme court.
9 J on the US S C?
9 Justices on the US Supreme Court
9 equals j on the s c?
nine judges on the supreme court
What r the dimensions of mutual inductance?
Obviously there is more than one way to do this. VL = Ldi/dt Volts has units of Joules/Coulomb: J/C i has units of Coulombs/second: C/s So di/di is C/s^2 L has units of J/C / C/s^2 = Js^2/C^2 Ic = CdV/dt => Ic/dV/dt = C/s / J/C-s = C/s * C-s/J = C^2/J C has units of C^2/J OR you could just type Q = CV => C = Q/V = C/J/C = C^2/J same answer R = V/I => J/C / C/s = J-s/C^2
What has the author J C S written?
J. C. S. has written: 'An Indian legend'
How many blood groups cows have?
9 They are A, B, C, F, J, L, M, S, and Z
What has the author J S C Browne written?
J. S. C. Browne has written: 'Basic theory of structures'
What has the author C J S Colthurst written?
C. J. S. Colthurst has written: 'Towards a resource centre'
Write a C program to remove duplicates in a string?
#include<stdio.h> main() { char s[50]; int i=0,j; printf("enter character string:"); while((s[i]=getchar())!='\n') { for(j=0;j<i;j++) if(s[j]==s[i]) i--; i++; } printf("after removing the duplicates the string is:"); for(j=0;j<i;j++) printf("%c",s[j]); }
How do you print the piramed of stars in c?
#include<stdio.h> int main() { char prnt = '*'; int i, j, s, nos = 0; for (i = 9; i >= 1; (i = i - 2)) { for (s = nos; s >= 1; s--) { printf(" "); } for (j = 1; j <= i; j++) { if ((i % 2) != 0 && (j % 2) != 0) { printf("%2c", prnt); } else { printf(" "); } } printf("\n"); nos++; } nos = 3; for (i = 3; i <= 9; (i = i + 2)) { for (s = nos; s >= 1; s--) { printf(" "); } for (j = 1; j <= i; j++) { if ((i % 2) != 0 && (j % 2) != 0) { printf("%2c", prnt); } else { printf(" "); } } nos--; printf("\n"); } return 0; }
