"One Cell in an Amoeba".
c + c + 1 = 49 2*c + 1 = 492*c = 48c = 24c + c + 1 = 49 2*c + 1 = 492*c = 48c = 24c + c + 1 = 49 2*c + 1 = 492*c = 48c = 24c + c + 1 = 49 2*c + 1 = 492*c = 48c = 24
If that's (c + 1) squared, (c + 1)(c + 1) = c^2 + 2c + 1
If that's + c3, the answer is c(c - 1)(c + 1)(c + 1)
use this strategy: integral of (b^x) dx = (b^x)/ln(b) + K [K is integration constant, b is not a variable]rewrite (1/c)^(1-x) = ((1/c)^1)*((1/c)^(-x)) = (1/c)*(c^x). (1/c) is a constant, so bring outside the integral, then let b = c in the formula above, and you have (1/c)*(c^x)/ln(c) + K
1°C is colder than 7°C. Temperature decreases as the number decreases in Celsius scale.
four a = 1 c = 3 a + c = 1 + 3 = 4
1/c also that depends on the value of c
Y=C+I C=C°+bY I=I° Y=C°+bY+I° Y-bY=C°+I° Y(1-b)=C°+I° Y=(C°+I°)/(1-b) Y+ΔY = (C°+I°+ΔI;ΔC)/(1-b) Y+ΔY = (C°+I°)/(1-b) + ΔI;ΔC/(1-b) = Y + ΔI;ΔC/(1-b) ΔY=ΔI;ΔC/(1-b) ΔY/ΔI;ΔC=1/(1-b) ΔY/ΔI=1/(1-b) ΔY/ΔC=1/(1-b)
1 c = 1/2 pints.
1 °C = 1 K and 1 ℃ = 1.8 °F
Here is the code to do it: #include<stdio.h> main() { int n, c, k, space = 1; //Here we ask for the number of rows would be : printf("Enter number of rows\n"); scanf("%d",&n); space = n - 1; //This is the first half of the diamond for ( k = 1 ; k <= n ; k++ ) { for ( c = 1 ; c <= space ; c++ ) printf(" "); space--; for ( c = 1 ; c <= 2*k-1 ; c++) printf("*"); printf("\n"); } space = 1; //Here is the second half of the diamond for ( k = 1 ; k <= n - 1 ; k++ ) { for ( c = 1 ; c <= space; c++) printf(" "); space++; for ( c = 1 ; c <= 2*(n-k)-1 ; c++ ) printf("*"); printf("\n"); } return 0; } Hope that helped :)
5b+c-43b-2c+1=1-38b-c