There are 7893600 permutations.
8^5=32,768 if letters can repeat 2,880 if letters can not be repeated.
Since in the word "party" no letters are repeated, the letters can be arranged in 5! ways, or 120.
There are 5 letters: a c e f and h.If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:5*5*5*5 = 54 = 625.
7,893,600 (seven million, 8 hundred ninety-three thousand, 600) combinations in English.
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5 (25th June 2011) LETTERS
If none of the letters were repeated, the answer would be 7!. However, the letters M & E are repeated. So, we need to divide the 7! by 2! twice to account for the two letters repeated twice. The solution is: 7! / (2! * 2!). This written out is: (7*6*5*4*3*2*1)/(2*1*2*1) or 1260.
Since no letters are repeated in the word prime, you can arrange the letters in the word prime 5! ways, or 120 ways.
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