To find the moles of Mn in MnO4, you need to consider the molar ratio between Mn and MnO4. In MnO4, there is one Mn atom. Therefore, the moles of Mn will be the same as the moles of MnO4, which is 4.18x10^4 moles.
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The oxidation state for manganese in Mn is 0, since it is in its elemental form.
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First start with what you know to find the total moles. Mn = 54.94g O = 16g 54.94g * 2 = 109.88g 16 * 3 = 48g Add these to get the weight of Mn2O3 which = 157.88 Divide 157.88 / 286 to get your total moles present, which = .552 Mols To find moles Mn, divide 54.94 by the total weight which is 157.88. This gives you your moles Mn, which is .348 mols. Since you have Mn2, multiply that number by 2 to get .695 mols Now you can divide Mol(Mn) by your total moles (.552) to get your moles Mn So .695 mol Mn2O3 / .552 mol Mn = 1.1 Mol Mn since 1.1 * 54.94 = 60 pct of the Molar Mass, this number makes sense since there is more Mn than O, the proportion seems correct. hope this helped! .
No
Yes
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2.3
No, Mn is a transition metal and is typically found in solid form rather than in aqueous solution.
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