First start with what you know to find the total moles.
Mn = 54.94g
O = 16g
54.94g * 2 = 109.88g
16 * 3 = 48g
Add these to get the weight of Mn2O3 which = 157.88
Divide 157.88 / 286 to get your total moles present, which = .552 Mols
To find moles Mn, divide 54.94 by the total weight which is 157.88. This gives you your moles Mn, which is .348 mols. Since you have Mn2, multiply that number by 2 to get .695 mols
Now you can divide Mol(Mn) by your total moles (.552) to get your moles Mn
So .695 mol Mn2O3 / .552 mol Mn = 1.1 Mol Mn
since 1.1 * 54.94 = 60 pct of the Molar Mass, this number makes sense since there is more Mn than O, the proportion seems correct.
hope this helped!
.
16.1201 grams KMnO4 (1 mole KMnO4/158.04 grams)(1 mole Mn/1 mole KMnO4)(6.022 X 1023/1 mole Mn)(1 mole Mn atoms/6.022 X 1023)
= 0.102000 moles of manganese atoms
----------------------------------------------------
Note that Avogadro's number is actually over itself in a form of one, so you do not need to go all the way in this, a formal set-up.
The molar mass of manganese dioxide is 86,9368 g.
3.00
3.00
This mass is 347,67 for KMnO4.
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
4.00
Atomic mass: 207.2 grams.455 moles × (6.02 × 1023) = 2.74 × 1023 atoms of lead
2.3 grams P (1mole P/30.97 grams) = 0.07427 moles Phosphorous 0.07427 moles P * 6.022 X 10^23 = 4.5 X 10^22 atoms of P in 2.3 grams P 4.5 X 10^22/6.022 X10^23 = 0.07427 moles of atoms in 2.3 grams of phosphorous
This mass is 347,67 for KMnO4.
To convert grams into atoms, you have to convert them into moles first. Get the molar mass and multiply it by the number of moles to get the atoms.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
0,666 moles
4,5 moles of copper are equivalent to 285,957 g.
2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
0
75,10 g of chlorine = 2,1183 moles
The formula mass of KMnO4 is 158.0Amount of KMnO4 = mass of sample / molar mass = 100/158.0 = 0.633 molThere are 0.633 moles in 100g of potassium permanganate.
1,93