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First start with what you know to find the total moles.
Mn = 54.94g
O = 16g
54.94g * 2 = 109.88g
16 * 3 = 48g
Add these to get the weight of Mn2O3 which = 157.88
Divide 157.88 / 286 to get your total moles present, which = .552 Mols
To find moles Mn, divide 54.94 by the total weight which is 157.88. This gives you your moles Mn, which is .348 mols. Since you have Mn2, multiply that number by 2 to get .695 mols
Now you can divide Mol(Mn) by your total moles (.552) to get your moles Mn
So .695 mol Mn2O3 / .552 mol Mn = 1.1 Mol Mn
since 1.1 * 54.94 = 60 pct of the Molar Mass, this number makes sense since there is more Mn than O, the proportion seems correct.
hope this helped!
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