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In Pakistan, Transformers are commonly used to step down high transmission voltages, such as 11,000 volts, to lower distribution voltages appropriate for consumer use. The voltage reduction is determined by the turns ratio of the transformer, which is designed to provide a specific output voltage. For instance, a transformer with a turns ratio that steps down 11,000 volts to 415 volts is typically designed for three-phase systems, where 415 volts is the standard voltage for industrial and commercial applications. This process allows for safe and efficient power distribution to end-users.

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3mo ago

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That type of transformer normally has about 99% efficiency so the full-load loss would be 1% or 6 kW.


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since at no load only excitation current(responsible for core loss ie iron loss) flow on the primary side so core loss current will be 1A and core loss = v1*i1*powerfactor. core loss = 1*11000*0.24= 2640watt.


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You really do need to use the correct symbols for electrical units! '2mva' indicates that you are describing '2 millivolt amperes', whereas I think you intend to mean 'megavolt amperes'? In which case the correct symbol is MV.A! (m = milli, M = mega) Note that the volt and ampere symbols are also capitalised.You can determine the primary current by dividing the MV.A rating of the transformer by its primary voltage rating:Ip = (2 x 106) / (11 x 103) = 182 A


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