36.6N and 25.9 N respectively.
To maintain a horizontal circular motion while the string makes an angle θ with the vertical, the bob must have a tangential speed ( v ) that can be determined using the relationship between gravitational force and the tension in the string. The vertical component of the tension must balance the weight of the bob, while the horizontal component provides the centripetal force required for circular motion. The formula for the tangential speed ( v ) can be expressed as ( v = \sqrt{g \cdot \tan(\theta) \cdot L} ), where ( g ) is the acceleration due to gravity and ( L ) is the length of the string.
He used the rope to stick up the lil kids PUTA, through the mouth up the PUTA again and into the mouth over and over again until eventually the boy exploded due to large tension from his PUTA ^^... Glad I can help
Trazodone is an antidepressant medication. It is thought to increase the activity of one of the brain chemicals (serotonin) which may become unbalanced and cause depression. Trazodoneis used to treat depression. It may also be used for relief of anxiety disorders (eg, sleeplessness, tension)Tramadol is a narcotic-like pain reliever. Tramadol is used to treat moderate to severe pain. Tramadol extended-release is used to treat moderate to severe chronic pain when treatment is needed around the clock
In music theory, the major dominant triads are built on the fifth scale degree of major scales and consist of the following: G major (in C major), D major (in G major), A major (in D major), E major (in A major), and B major (in E major). Minor dominant triads, often used in harmonic minor contexts, include: E minor (in A minor), B minor (in E minor), F# minor (in B minor), C# minor (in F# minor), and G# minor (in C# minor). These triads are essential for creating tension and resolution in Western music.
The vertical speed of a horizontal taut string depends on the wave speed because the tension in the string is responsible for transmitting the wave along its length. The wave speed is determined by the tension in the string and the properties of the medium it is traveling through, which in turn affects the vertical motion of the string as the wave propagates.
There are mainly two types of bike frame dropouts: horizontal and vertical. Horizontal dropouts allow for easy adjustment of chain tension and wheel position, while vertical dropouts are simpler and more common. The type of dropout can affect the ease of wheel removal, chain tension, and overall stability of the bike.
The tension in the cable at the end where the window washer stands is 615 N. This tension is calculated by summing the torques about the other end of the scaffold. The tension at the other end can be found by balancing the vertical forces acting on the scaffold.
Vertical stressors are things like attitudes, labels, family secrets, and myths that are passed through the generations of a family. Horizontal stressors include things like job loss, the loss of a loved one, and moving.
Angles significantly influence tension in a system, particularly in scenarios involving ropes or cables. When a force is applied at an angle, the tension must counteract not only the weight of the object being supported but also the components of the force acting in different directions. As the angle increases, the vertical component of the tension decreases, requiring greater tension to maintain equilibrium. Conversely, at smaller angles, the vertical component increases, resulting in lower overall tension needed to support the load.
The tension in each cable can be found by setting up force equilibrium equations in the horizontal and vertical directions. Since the traffic light is at rest, the sum of the vertical forces must equal zero. The tension in each cable will be mg/√2, where m is the mass of the traffic light and g is the acceleration due to gravity.
weight of crate would be 226 lb...saw it in back of the book
To determine the tension in each chain supporting a weight of 900N, we can use trigonometry based on the lengths of the chains and the vertical weight they support. Let's denote the tension in the 4m chain as T1 and in the 3m chain as T2. Assuming the chains are at angles θ1 and θ2 with the vertical, we can set up the equations using the vertical components of the tensions: T1 * cos(θ1) + T2 * cos(θ2) = 900N. The specific angles would be needed to calculate the exact tensions.
z = -H/g (cosh (gx/H)-1) where z = vertical distance H = Horizontal component of cable force g = weight of cable / unit of lenght x = horizontal distance and dz/dx = -sinh(gx/H) V = - H sinh(gx/H) where V = vertical component of cable force N = H - gz where N = tension force in the cable
To calculate tension in a cable, take the mass of the section of cable and consider the force applied straight downward due to the acceleration of gravity. Divide that by two because the cable is supported at both ends. That is the force applied to one support in a downward direction. Now, consider the angle of the cable relative to vertical at the support. Using simple vector analysis, determine the force in the direction of the cable. That is the tension of the cable.If you also calculate the horizontal force vector at the support, that would be the force pulling the two supports together, although that is not usually an issue because there is often another section of cable on the opposite side of the support which balances the horizontal force vector.
If the ropes make the same angle with the vertical, then the tension in each rope will be the same. This is because the angles are equal and the forces are balanced. The tension in each rope will be equal to each other.
There can never be TENSION in the Earth (gravity is squeezing the whole Earth up).So no type of fault can be the product of tension.Faults of varying varieties happen when the relative magnitude of the maximum and minimum compression forces change and or change direction.Normally the vertical force (gravity) is the maximum force and transverse faults (with vertical fault planes) happen the ratio of the horizontal compressive forces (which are at tight angles to one another) exceeds the shear strength of the rock.Normal faults occur when the ratio between the gravity and one or other of the horizontal forces exceeds the shear strength of the rock.Reverse faults occur when the ratio between an horizontal force and the vertical force exceeds the shear strength of the rock.