Im assuming you mean Mg(OH)2 and not MgOHThe reaction between Mg(OH)2 and HCl is as follows: Mg(OH)2 (aq) + 2HCl (aq) -> MgCl2 (aq) + 2H2O (l)First the number of mole is found: n(HCl) = c × v = 0.100M × 0.200L = 0.0200mol (to 3 significant figures)Next we find the number of mole of Mg(OH)2:n(Mg(OH)2) ÷ n(HCl) = Coefficient of Mg(OH)2 ÷ Coefficient of HCl n(Mg(OH)2) ÷ n(HCl) = 1 ÷ 2 therefore:n(Mg(OH)2) = (1 ÷ 2) × n(HCl) n(Mg(OH)2) = (1 ÷ 2) × 0.0200moln(Mg(OH)2) = 0.0100mol (to 3 significant figures)Finally we calculate the volume of Mg(OH)2 reacted:v(Mg(OH)2) = n ÷ cv(Mg(OH)2) = 0.0100mol ÷ 0.500MThereforev(Mg(OH)2) = 0.0200L (to 3 significant figures) = 20.0ml (to 3 significant figures)
The balanced chemical equation for the reaction between HCl and Mg is: Mg + 2HCl -> MgCl2 + H2. One mole of Mg reacts with 2 moles of HCl. Calculate the moles of Mg in 5.2 grams using the molar mass of Mg. Then use the mole ratio to find the moles of HCl needed, and finally calculate the mass of HCl using its molar mass.
The products of the neutralization reaction between hydrochloric acid (HCl) and magnesium hydroxide (Mg(OH)2) are magnesium chloride (MgCl2) and water (H2O). This reaction is represented by the equation: 2HCl + Mg(OH)2 → MgCl2 + 2H2O.
Hydrochloric acid + magnesium ---> Magnesium chloride + hydrogen gasUnbalanced: HCl + Mg ---> MgCl2 + H2Balanced: 2HCl + Mg ---> MgCl2 + H2
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To neutralize the 0.10 M HCl in 25 mL, we first calculate the moles of HCl present: 0.10 mol/L * 0.025 L = 0.0025 mol HCl. Since 1 mole of HCl reacts with 2 moles of Mg(OH)2 (according to the balanced chemical equation), we need 0.0050 moles of Mg(OH)2. The molar mass of Mg(OH)2 is 58.3 g/mol, so we need 0.0050 mol * 58.3 g/mol ≈ 0.29 grams of Mg(OH)2.
The balanced equation for the reaction between hydrochloric acid (HCl) and magnesium (Mg) is 2 HCl + Mg → MgCl2 + H2. This equation shows that when hydrochloric acid reacts with magnesium, magnesium chloride and hydrogen gas are produced.
The reaction is balanced, so the mole ratio of Mg to HCl is 1:2. Calculate the molar mass of HCl (1 mol HCl = 1g + 1g = 36.5g), then use stoichiometry to convert the mass of Mg to moles of HCl. Finally, divide the mass of Mg by 1 (from the ratio 1:2) and multiply by the molar mass of HCl to find the mass needed.
To determine the theoretical yield of magnesium chloride (MgCl₂) from the reaction of magnesium hydroxide (Mg(OH)₂) with hydrochloric acid (HCl), we first identify the balanced chemical equation: Mg(OH)₂ + 2 HCl → MgCl₂ + 2 H₂O. The molar mass of Mg(OH)₂ is approximately 58.3197 g/mol, and that of MgCl₂ is about 95.211 g/mol. Calculating the moles of Mg(OH)₂ in 50.6 g gives about 0.868 moles, while 45.0 g of HCl corresponds to about 1.23 moles. Since the reaction requires 2 moles of HCl for every mole of Mg(OH)₂, HCl is in excess. The limiting reagent is Mg(OH)₂, producing 0.868 moles of MgCl₂. Therefore, the theoretical yield of MgCl₂ is approximately 82.7 grams (0.868 moles × 95.211 g/mol).
Mg + 2HCl = MgCl2 + H2 SO magnesium chloride and Hydrogen gas
The balanced equation for the reaction between hydrochloric acid (HCl) and magnesium (Mg) to form magnesium chloride (MgCl2) and hydrogen gas (H2) is: 2 HCl (aq) + Mg (s) → MgCl2 (aq) + H2 (g)
2HCl + Mg(OH)2 ------> H2O + MgCl2